Reputation: 35
I'm working with Apache FOP v.1.0 (latest) on Windows XP and I want to use parameters. I used different parameter syntaxes, but "fop" doesn't use it. In the documentation is written: "-param name value".
Parts of my XML file:
<letter position="1">
I have in my XSLT file:
<xsl:param name="position"/>
<xsl:for-each select="letter[@position=$position]">
The following works:
<xsl:for-each select="letter[@position=1]">
And this works also:
<xsl:param name="position" select="1"/>
<xsl:for-each select="letter[@position=$position]">
So FOP just doesn't gets any input.
Commands I tried, which didn't work:
fop -param position 1 -xml data.xml -xsl stylesheet.xsl -pdf output.pdf
fop -xml data.xml -param position 1 -xsl stylesheet.xsl -pdf output.pdf
fop -xml data.xml -xsl stylesheet.xsl -param position 1 -pdf output.pdf
fop -xml data.xml -xsl stylesheet.xsl -pdf output.pdf -param position 1
fop -xml data.xml -xsl stylesheet.xsl -pdf output.pdf -param "position" 1
fop -xml data.xml -xsl stylesheet.xsl -pdf output.pdf -param position "1"
fop -xml data.xml -xsl stylesheet.xsl -pdf output.pdf -param "position" "1"
fop -xml data.xml -xsl stylesheet.xsl -param "position" 1 -pdf output.pdf
fop -xml data.xml -xsl stylesheet.xsl -param position "1" -pdf output.pdf
fop -xml data.xml -xsl stylesheet.xsl -param "position" "1" -pdf output.pdf
fop -xml data.xml -param "position" 1 -xsl stylesheet.xsl -pdf output.pdf
fop -xml data.xml -param position "1" -xsl stylesheet.xsl -pdf output.pdf
fop -xml data.xml -param "position" "1" -xsl stylesheet.xsl -pdf output.pdf
fop -param "position" 1 -xml data.xml -xsl stylesheet.xsl -pdf output.pdf
fop -param position "1" -xml data.xml -xsl stylesheet.xsl -pdf output.pdf
fop -param "position" "1" -xml data.xml -xsl stylesheet.xsl -pdf output.pdf
I looked at Processing FOP with parameters but they don't give a working example.
Many thanks,
Upvotes: 2
Views: 2768
Reputation: 52858
Is your xsl:param
a child of xsl:stylesheet
or do you have it in an xsl:template
? It should be a direct child of xsl:stylesheet
.
Here is a working example...
XML Input (param_test.xml)
<doc>
<letter position="1">position 1</letter>
<letter position="2">position 2</letter>
<letter position="3">position 3</letter>
<letter position="4">position 4</letter>
</doc>
XSLT 1.0 (param_test.xsl)
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:param name="position"/>
<xsl:template match="/doc">
<fo:root xmlns:fo="http://www.w3.org/1999/XSL/Format">
<fo:layout-master-set>
<fo:simple-page-master master-name="my-page" page-width="8.5in" page-height="11in">
<fo:region-body margin="1in" margin-top="1.5in" margin-bottom="1.5in"/>
</fo:simple-page-master>
</fo:layout-master-set>
<fo:page-sequence master-reference="my-page">
<fo:flow flow-name="xsl-region-body">
<xsl:for-each select="letter[@position=$position]">
<fo:block>
<xsl:value-of select="."/>
</fo:block>
</xsl:for-each>
</fo:flow>
</fo:page-sequence>
</fo:root>
</xsl:template>
</xsl:stylesheet>
FOP command line (Version 1.0 on Windows XP)
fop -xml param_test.xml -xsl param_test.xsl -pdf param_test.pdf -param position 1
PDF Output (param_test.pdf)
Upvotes: 1