Vossi
Vossi

Reputation: 231

Java JAXB - link output to XSLT document

I am producing a XML file by the help of JAXB.

public String getPrices() {
    StringWriter writer = new StringWriter();
    JAXBContext context;
    try {
        context = JAXBContext.newInstance(AllMerchandises.class);
        Marshaller m = context.createMarshaller();
        m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE);
        m.marshal(this.allMerchandises, writer);
    } catch (JAXBException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    return writer.toString();
}

the resulting XML String looks like this.

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<ns2:merchandises xmlns:ns2="example/test/workspace">
<merchandise id="1">
    <name>Cat</name>
    <price>50</price>
</merchandise>
<merchandise id="2">
    <name>Dog</name>
    <price>100</price>
</merchandise>
<merchandise id="3">
    <name>Ape</name>
    <price>150</price>
</merchandise>
<merchandise id="4">
    <name>Gorilla</name>
    <price>200</price>
</merchandise>
<merchandise id="5">
    <name>Elephant</name>
    <price>250</price>
</merchandise>
</ns2:merchandises>

It is my task that the document could be showed a little bit designed in a browser by using XSLT. Therefor I need to include the .xsl in my XML file. Is there a maybe a way to tell the JAXB marshaller to make a inclusion? What could I do otherwise? I need to include sth like this as 2nd line:

<?xml-stylesheet type="text/xsl" href="myfile.xsl"?>

thanks for every good idea

Upvotes: 0

Views: 1716

Answers (1)

Vossi
Vossi

Reputation: 231

Finally I ended up using the same solution as described in this thread.

Making JAXB generate an XML processing instruction

Upvotes: 1

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