CODEWITHSUNDEEP
pythonregex
jianjun
jianjun

Reputation: 33

Python re-match with space and new line

html6="""
<p<ins style="background:#e6ffe6;">re><code</ins>>
int aint bint c<ins style="background:#e6ffe6;"></code></ins></p<ins style="background:#e6ffe6;">re</ins>><p>int d</p>
"""

Html6 and Html7 is the same , just Html7 has "\n"

html7="""
<p<ins style="background:#e6ffe6;">re><code</ins>>int a
int b
int c<ins style="background:#e6ffe6;">
</code></ins></p<ins style="background:#e6ffe6;">re</ins>>
<p>int d</p>
"""

p_to_pre_code_pattern = re.compile(
"""<p
<(?P<action_tag>(del|ins)) (?P<action_attr>.*)>re><code</(?P=action_tag)>
>
(?P<text>.*?)
<(?P=action_tag) (?P=action_attr)>
</code></(?P=action_tag)>
</p
<(?P=action_tag) (?P=action_attr)>re</(?P=action_tag)>
>""",re.VERBOSE)


print re.match(p_to_pre_code_pattern,html6)    
print re.match(p_to_pre_code_pattern,html7)

both html6 and html7 will not match ? ,but if i replace the "\n" to "" , it will much both .

print re.match(p_to_pre_code_pattern,html6.replace("\n",""))    
print re.match(p_to_pre_code_pattern,html7.replace("\n",""))

I want to know how should I change the p_to_pre_code_pattern that I will match both html6 and html7 without calling replace("\n","")) ?

Upvotes: 2

Views: 1325

Answers (1)

kev
kev

Reputation: 161864

Maybe you miss the re.DOTALL flag when call re.compile(..., re.VERBOSE|re.DOTALL)

re.S 
re.DOTALL 

Make the '.' special character match any character at all, including a newline;
without this flag, '.' will match anything except a newline.

Upvotes: 1

Related Questions