Reputation: 481
I am trying to transform XML into another XML file but unsuccessfully changing a flat element into an expanded element.
The output should be identical except DateOfBirth should be changed to:
<DateOfBirth>
<FullDate xmlns="cds_dt">1966-02-11</FullDate>
</DateOfBirth>
Here are the input files I am using:
Input
*****
<?xml version="1.0" encoding="utf-8"?>
<RootRec xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="cds">
<MyRecord>
<Demographics>
<Names>
<LegalName namePurpose="L" xmlns="cds_dt">
<FirstName>
<Part>Jason</Part>
<PartType>GIV</PartType>
</FirstName>
<LastName>
<Part>Smith</Part>
<PartType>FAMC</PartType>
</LastName>
<OtherName>
<Part>Lauren</Part>
<PartType>GIV</PartType>
</OtherName>
</LegalName>
</Names>
<DateOfBirth>1966-02-11</DateOfBirth>
<Demographics>
<MyRecord>
</RootRec>
XSL file
********
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>
<!--Identity Template. This will copy everything as-is.-->
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<!--expand "DateOfBirth" element to /DateOfBirth/FullDate element.-->
<xsl:template match="RootRec/MyRecord/Demographics/DateOfBirth">
<DateOfBirth>
<FullDate><xsl:value-of select="DateOfBirth"/></FullDate>
</DateOfBirth>
</xsl:template>
</xsl:stylesheet>
Upvotes: 1
Views: 191
Reputation: 3443
It should be
<FullDate><xsl:value-of select="."/></FullDate>
since you're already selecting the DateOfBirth in the match=""
You also have missing /
in the three closing tags before the document end, and your namespace names are invalid because they must be absolute URIs.
Good luck.
Upvotes: 0
Reputation: 243549
This transformation:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:x="cds">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="x:DateOfBirth/text()">
<xsl:element name="FullDate" xmlns="cds_dt"><xsl:value-of select="."/></xsl:element>
</xsl:template>
</xsl:stylesheet>
when applied on the provided (corrected to be made wellformed) XML document:
<RootRec
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema"
xmlns="cds">
<MyRecord>
<Demographics>
<Names>
<LegalName namePurpose="L" xmlns="cds_dt">
<FirstName>
<Part>Jason</Part>
<PartType>GIV</PartType>
</FirstName>
<LastName>
<Part>Smith</Part>
<PartType>FAMC</PartType>
</LastName>
<OtherName>
<Part>Lauren</Part>
<PartType>GIV</PartType>
</OtherName>
</LegalName>
</Names>
<DateOfBirth>1966-02-11</DateOfBirth>
</Demographics>
</MyRecord>
</RootRec>
produces the wanted, correct result:
<RootRec xmlns="cds" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<MyRecord>
<Demographics>
<Names>
<LegalName xmlns="cds_dt" namePurpose="L">
<FirstName>
<Part>Jason</Part>
<PartType>GIV</PartType>
</FirstName>
<LastName>
<Part>Smith</Part>
<PartType>FAMC</PartType>
</LastName>
<OtherName>
<Part>Lauren</Part>
<PartType>GIV</PartType>
</OtherName>
</LegalName>
</Names>
<DateOfBirth>
<FullDate xmlns="cds_dt">1966-02-11</FullDate>
</DateOfBirth>
</Demographics>
</MyRecord>
</RootRec>
Explanation: Overriding the identity rule.
Upvotes: 2