Reputation: 5175
Here is the code
I have written a server and client. But when i run them, (as you can see in the last program), I get the following error:
Whoop s! java.net.BindException: Address already in use 6666
6666 is the port no. i specified.
import java.net.*;
import java.io.*;
import java.lang.*;
public class processSendHelper
{
Process p;
String address;
int port;
long msg_data;
processSendHelper(int pid, int current_round, long address, long msg_data, int port)
{
try
{
ServerSocket sSoc = new ServerSocket(port);
Socket inSoc = sSoc.accept();
msg_Thread msgT = new msg_Thread(inSoc, msg_data);
msgT.start();
Thread.sleep(5000);
sSoc.close();
}
catch(Exception e)
{
System.out.println("Whoop s! " + e.toString());
}
}
}
/* sends out (or rather just makes available) the provided msg
* */
class msg_Thread extends Thread
{
Socket threadSoc;
long msg_data;
msg_Thread (Socket inSoc, long msg_data)
{
threadSoc = inSoc;
this.msg_data = msg_data;
}
public void run()
{
try
{
PrintStream SocOut = new
PrintStream(threadSoc.getOutputStream());
SocOut.println(msg_data);
}
catch (Exception e)
{
System.out.println("Whoops!" + e.toString());
}
try
{
threadSoc.close();
}
catch (Exception e)
{
System.out.println("Oh no! " +
e.toString());
}
}
}
import java.net.*;
import java.io.*;
public class processReceiveHelper
{
Socket appSoc;
BufferedReader in;
String message;
String host;
int port;
processReceiveHelper(String host,int port)
{
try
{
appSoc = new Socket(host,port);
in = new BufferedReader(new InputStreamReader(appSoc.getInputStream()));
message = in.readLine();
System.out.println(message);
/* Tokenizer code comes here
* Alongwith the code for
* updating the process object's
* data
* */
}
catch (Exception e)
{
System.out.println("Died... " +
e.toString());
}
}
}
public class Orchestrator
{
public static void main(String[] args)
{
processSendHelper psh = new processSendHelper(1, 2, 1237644, 6666, 2002);
processReceiveHelper prh = new processReceiveHelper("localhost", 2002);
}
}
I found the problem. The reason was that i was running both the server and client from the same main program.
the following worked:
Upvotes: 0
Views: 371
Reputation: 1239
Does it happen when you run the program for the second time? You may want to setReuseAddress(true) on this socket.
Upvotes: 1
Reputation: 44808
That means that the port 6666 is already being used. There are two main causes/solutions for this:
Upvotes: 1
Reputation: 4211
That means there is already an application operating on port 6666 preventing your Java application using it. However, it is equally possible there is a running process of your Java application still holding onto 6666. Terminate any running java processes and try re-running the code - if it still fails then you have some other application using 6666 and you would be better using a different port.
Upvotes: 2