Reputation: 3472
If I have an array full of information, is there any way I can a default for values to be returned if the key doesn't exist?
function items() {
return array(
'one' => array(
'a' => 1,
'b' => 2,
'c' => 3,
'd' => 4,
),
'two' => array(
'a' => 1,
'b' => 2,
'c' => 3,
'd' => 4,
),
'three' => array(
'a' => 1,
'b' => 2,
'c' => 3,
'd' => 4,
),
);
}
And in my code
$items = items();
echo $items['one']['a']; // 1
But can I have a default value to be returned if I give a key that doesn't exist like,
$items = items();
echo $items['four']['a']; // DOESN'T EXIST RETURN DEFAULT OF 99
Upvotes: 58
Views: 92510
Reputation: 651
As of PHP7.0
You may use the null coalescing operator: ??
$value = $items['four']['a'] ?? 99;
echo $value;
# or simply
echo $items['four']['a'] ?? 99;
As of PHP7.4
You could instead use the null coalescing assignment operator if you want to additionally assign the default value to the array key if empty.
$items['four']['a'] ??= 99;
echo $items['four']['a'];
For PHP <=5.x
If you can guarantee that 'four' and 'a' keys always exist and is either a truthy or falsy value, then you may use the ternary operator with empty middle part: ?:
However, if the array keys are not guaranteed to exist, this may give you errors, so be careful to check with isset()
or !empty()
(see the long-form answer below).
$value = $items['four']['a'] ?: 99;
echo $value;
All versions of PHP support the long-form ternary operator:
$value = !empty($items['four']['a']) ? $items['four']['a'] : 99;
echo $value;
Note that this does not return 99 if and only if the key 'a'
is not set in items['four']
. Instead, it returns 99 if and only if the value $items['four']['a']
is either unset or a falsy value value like an empty string (''
), empty array, NULL
, 0
, or FALSE
.
Upvotes: 11
Reputation: 182
Currently using of php 7.2
>>> $a = ["cat_name"=>"Beverage", "details"=>"coca cola"];
=> [
"cat_name" => "Beverage",
"details" => "coca cola",
]
>>> $a['price']
PHP Notice: Undefined index: price in Psy Shell code on line 1
=> null
>>> $a['price'] ?? null ? "It has price key" : "It does not have price key"
=> "It does not have price key"
Upvotes: 0
Reputation: 10361
As of PHP 7, there is a new operator specifically designed for these cases, called Null Coalesce Operator.
So now you can do:
echo $items['four']['a'] ?? 99;
instead of
echo isset($items['four']['a']) ? $items['four']['a'] : 99;
There is another way to do this prior the PHP 7:
function get(&$value, $default = null)
{
return isset($value) ? $value : $default;
}
And the following will work without an issue:
echo get($item['four']['a'], 99);
echo get($item['five'], ['a' => 1]);
But note, that using this way, calling an array property on a non-array value, will throw an error. E.g.
echo get($item['one']['a']['b'], 99);
// Throws: PHP warning: Cannot use a scalar value as an array on line 1
Also, there is a case where a fatal error will be thrown:
$a = "a";
echo get($a[0], "b");
// Throws: PHP Fatal error: Only variables can be passed by reference
At final, there is an ugly workaround, but works almost well (issues in some cases as described below):
function get($value, $default = null)
{
return isset($value) ? $value : $default;
}
$a = [
'a' => 'b',
'b' => 2
];
echo get(@$a['a'], 'c'); // prints 'c' -- OK
echo get(@$a['c'], 'd'); // prints 'd' -- OK
echo get(@$a['a'][0], 'c'); // prints 'b' -- OK (but also maybe wrong - it depends)
echo get(@$a['a'][1], 'c'); // prints NULL -- NOT OK
echo get(@$a['a']['f'], 'c'); // prints 'b' -- NOT OK
echo get(@$a['c'], 'd'); // prints 'd' -- OK
echo get(@$a['c']['a'], 'd'); // prints 'd' -- OK
echo get(@$a['b'][0], 'c'); // prints 'c' -- OK
echo get(@$a['b']['f'], 'c'); // prints 'c' -- OK
echo get(@$b, 'c'); // prints 'c' -- OK
Upvotes: 87
Reputation: 8708
The question is very old, but maybe my solution is still helpful. For projects where I need "if array_key_exists" very often, such as Json parsing, I have developed the following function:
function getArrayVal($arr, $path=null, $default=null) {
if(is_null($path)) return $arr;
$t=&$arr;
foreach(explode('/', trim($path,'/')) As $p) {
if(!array_key_exists($p,$t)) return $default;
$t=&$t[$p];
}
return $t;
}
You can then simply "query" the array like:
$res = getArrayVal($myArray,'companies/128/address/street');
This is easier to read than the equivalent old fashioned way...
$res = (isset($myArray['companies'][128]['address']['street']) ? $myArray['companies'][128]['address']['street'] : null);
Upvotes: 4
Reputation: 617
In PHP7, as Slavik mentioned, you can use the null coalescing operator: ??
Link to the PHP docs.
Upvotes: -1
Reputation: 4905
You can use DefaultArray from Non-standard PHP library. You can create new DefaultArray from your items:
use function \nspl\ds\defaultarray;
$items = defaultarray(function() { return defaultarray(99); }, $items);
Or return DefaultArray from the items()
function:
function items() {
return defaultarray(function() { return defaultarray(99); }, array(
'one' => array(
'a' => 1,
'b' => 2,
'c' => 3,
'd' => 4,
),
'two' => array(
'a' => 1,
'b' => 2,
'c' => 3,
'd' => 4,
),
'three' => array(
'a' => 1,
'b' => 2,
'c' => 3,
'd' => 4,
),
));
}
Note that we create nested default array with an anonymous function function() { return defaultarray(99); }
. Otherwise, the same instance of default array object will be shared across all parent array fields.
Upvotes: 0
Reputation: 3245
Use Array_Fill() function
http://php.net/manual/en/function.array-fill.php
$default = array(
'a' => 1,
'b' => 2,
'c' => 3,
'd' => 4,
);
$arr = Array_Fill(1,3,$default);
print_r($arr);
This is the result:
Array
(
[1] => Array
(
[a] => 1
[b] => 2
[c] => 3
[d] => 4
)
[2] => Array
(
[a] => 1
[b] => 2
[c] => 3
[d] => 4
)
[3] => Array
(
[a] => 1
[b] => 2
[c] => 3
[d] => 4
)
)
Upvotes: 2
Reputation: 17762
This should do the trick:
$value = isset($items['four']['a']) ? $items['four']['a'] : 99;
A helper function would be useful, if you have to write these a lot:
function arr_get($array, $key, $default = null){
return isset($array[$key]) ? $array[$key] : $default;
}
Upvotes: 22
Reputation: 7025
I know this is an old question, but my Google search for "php array default values" took me here, and I thought I would post the solution I was looking for, chances are it might help someone else.
I wanted an array with default option values that could be overridden by custom values. I ended up using array_merge.
Example:
<?php
$defaultOptions = array("color" => "red", "size" => 5, "text" => "Default text");
$customOptions = array("color" => "blue", "text" => "Custom text");
$options = array_merge($defaultOptions, $customOptions);
print_r($options);
?>
Outputs:
Array
(
[color] => blue
[size] => 5
[text] => Custom text
)
Upvotes: 91
Reputation: 3932
I don't know of a way to do it precisely with the code you provided, but you could work around it with a function that accepts any number of arguments and returns the parameter you're looking for or the default.
Usage:
echo arr_value($items, 'four', 'a');
or:
echo arr_value($items, 'four', 'a', '1', '5');
Function:
function arr_value($arr, $dimension1, $dimension2, ...)
{
$default_value = 99;
if (func_num_args() > 1)
{
$output = $arr;
$args = func_gets_args();
for($i = 1; $i < func_num_args(); $i++)
{
$outout = isset($output[$args[$i]]) ? $output[$args[$i]] : $default_value;
}
}
else
{
return $default_value;
}
return $output;
}
Upvotes: 0
Reputation: 265201
Not that I know of.
You'd have to check separately with isset
echo isset($items['four']['a']) ? $items['four']['a'] : 99;
Upvotes: 3