CODEWITHSUNDEEP
bashsedawk
yasar
yasar

Reputation: 13728

How to add to the end of lines containing a pattern with sed or awk?

Here is example file:

somestuff...
all: thing otherthing
some other stuff

What I want to do is to add to the line that starts with all: like this:

somestuff...
all: thing otherthing anotherthing
some other stuff

Upvotes: 98

Views: 187065

Answers (6)

chenchuk
chenchuk

Reputation: 5742

Here is another simple solution using sed. 

$ sed -i 's/all.*/& anotherthing/g' filename.txt

Explanation:

all.* means all lines started with 'all'.

& represent the match (ie the complete line that starts with 'all')

then sed replace the former with the later and appends the ' anotherthing' word

Upvotes: 9

fedorqui
fedorqui

Reputation: 289495

You can append the text to $0 in awk if it matches the condition:

awk '/^all:/ {$0=$0" anotherthing"} 1' file

Explanation

  • /patt/ {...} if the line matches the pattern given by patt, then perform the actions described within {}.
  • In this case: /^all:/ {$0=$0" anotherthing"} if the line starts (represented by ^) with all:, then append anotherthing to the line.
  • 1 as a true condition, triggers the default action of awk: print the current line (print $0). This will happen always, so it will either print the original line or the modified one.

Test

For your given input it returns:

somestuff...
all: thing otherthing anotherthing
some other stuff

Note you could also provide the text to append in a variable:

$ awk -v mytext=" EXTRA TEXT" '/^all:/ {$0=$0mytext} 1' file
somestuff...
all: thing otherthing EXTRA TEXT
some other stuff

Upvotes: 19

glenn jackman
glenn jackman

Reputation: 246744

In bash:

while read -r line ; do
    [[ $line == all:* ]] && line+=" anotherthing"
    echo "$line"
done < filename

Upvotes: 6

Manlio
Manlio

Reputation: 10865

Solution with awk:

awk '{if ($1 ~ /^all/) print $0, "anotherthing"; else print $0}' file

Simply: if the row starts with all print the row plus "anotherthing", else print just the row.

Upvotes: 5

izidor
izidor

Reputation: 4144

This should work for you

sed -e 's_^all: .*_& anotherthing_'

Using s command (substitute) you can search for a line which satisfies a regular expression. In the command above, & stands for the matched string.

Upvotes: 10

user219882
user219882

Reputation: 15834

This works for me

sed '/^all:/ s/$/ anotherthing/' file

The first part is a pattern to find and the second part is an ordinary sed's substitution using $ for the end of a line.

If you want to change the file during the process, use -i option

sed -i '/^all:/ s/$/ anotherthing/' file

Or you can redirect it to another file

sed '/^all:/ s/$/ anotherthing/' file > output

Upvotes: 191

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