CODEWITHSUNDEEP
linuxshellunixsh
biztiger
biztiger

Reputation: 1487

List all directories with spaces in their name

I want to list all directories using a shell script. I am using the following code:

DIR="$1"

if [ $# -ne 1 ]
then
    echo "Usage: $0 {dir-name}"
exit 1
fi

cd "$DIR"
SAVEIFS=$IFS
IFS=$(echo -en "\n\b")
for user in $( ls -d */)
do
  for dirs in $( ls -d $PWD/$user*)
  do
    echo $PWD/$user/$dirs;
  done
done
IFS=$SAVEIFS

It is working for me if that directory don't have any spaces on it, else it split the output for every spaces on it. I got the following output:

abhinaba@abhinaba-desktop:~/software$ sh test.sh /media/2C44138344134F48/RB1
ls: cannot access /m: No such file or directory
ls: cannot access dia/2C44138344134F48/RB1/VB*: No such file or directory
ls: cannot access /m: No such file or directory
ls: cannot access dia/2C44138344134F48/RB1/DLI*: No such file or directory
ls: cannot access /m: No such file or directory
ls: cannot access dia/2C44138344134F48/RB1/3001/*: No such file or directory
ls: cannot access /m: No such file or directory
ls: cannot access dia/2C44138344134F48/RB1/VB*: No such file or directory
ls: cannot access /m: No such file or directory
ls: cannot access dia/2C44138344134F48/RB1/DLI*: No such file or directory
ls: cannot access /m: No such file or directory
ls: cannot access dia/2C44138344134F48/RB1/3002/*: No such file or directory
ls: cannot access /m: No such file or directory
ls: cannot access dia/2C44138344134F48/RB1/VB*: No such file or directory
ls: cannot access /m: No such file or directory
ls: cannot access dia/2C44138344134F48/RB1/DLI*: No such file or directory
ls: cannot access /m: No such file or directory
ls: cannot access dia/2C44138344134F48/RB1/3003/*: No such file or directory

Upvotes: 2

Views: 4994

Answers (3)

JScoobyCed
JScoobyCed

Reputation: 10413

EDITED: removed ls to optimize the script (from tripleee)

If you use BASH shell:

#!/bin/bash

SAVEIFS=$IFS
IFS=$(echo -en "\n\b")
DIR="$1"

if [ $# -ne 1 ]
 then
 echo "Usage: $0 {dir-name}"
 exit 1
fi

cd "$DIR"

for user in $(ls -d */)
 do
 for dirs in $(ls -d $user*)
  do
  echo $dirs
 done
done

IFS=$SAVEIFS

Run the above "test.sh" script like this:

bash test.sh /media/2C44138344134F48/RB1

or simply (if you are already in BASH and you have set the eXecutable flag)

./test.sh /media/2C44138344134F48/RB1

Reference

Upvotes: 2

Wes Hardaker
Wes Hardaker

Reputation: 22252

It would actually be easiest to use find:

find PATH -type d -name '* *'

Or if you need to do something with each result, consider piping it to xargs

find PATH -type d -name '* *' -print0 | xargs -0 run-some-command

Or if you just want all the directories safely escaped into arguments then: 

find PATH -type d -print0 | xargs -0 run-some-command

Inside run-some-command, each argument to the script will be properly set to each directory name regardless of what characters it contains.

Upvotes: 2

dAm2K
dAm2K

Reputation: 10329

The simple script below will do what you need.

#!/bin/bash

function usage() {
        echo "Usage: `basename $0` <dir-name>"
}


if [ "x$1" = "x" ]
then
        usage
        exit 0
fi

find "$1" -type 'd'

Upvotes: 0

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