Reputation: 6286
When I try to syncdb I get the error Menu is not a valid class Name.
How can I resolve that relationship case :
class MenuItem(model.Models)
title = models.CharField(max_length=200)
submenus = models.ManyToManyField(Menu, blank=True, null=True)
class Menu(Container):
links = models.ManyToManyField(MenuItem)
Upvotes: 5
Views: 3673
Reputation: 169264
From the Django book:
If you need to create a relationship on a model that has not yet been defined, you can use the name of the model, rather than the model object itself:
E.g.:
class MenuItem(model.Models)
title = models.CharField(max_length=200)
submenus = models.ManyToManyField('Menu', blank=True, null=True)
^ ^
Edit:
As Francis mentions (and as is written in the documentation):
It doesn't matter which model has the ManyToManyField, but you should only put it in one of the models -- not both.
Upvotes: 10
Reputation: 10919
One of these models has a many to many, the other one uses Django's reverse relations (https://docs.djangoproject.com/en/dev/topics/db/queries/#following-relationships-backward)
So how I would set it up:
class Menu(Container):
links = models.ManyToManyField(MenuItem)
class MenuItem(model.Models)
title = models.CharField(max_length=200)
Then when I wanted a MenuItem's Menus:
menu_item_instance.menu_set.all()
Upvotes: 6