CODEWITHSUNDEEP
c++c++11constexpr
smallB
smallB

Reputation: 17100

constexpr and bizzare error

I'm having: 

constexpr bool is_concurrency_selected()const
    {
        return ConcurrentGBx->isChecked();//GBx is a groupbox with checkbox
    }

and I'm getting error: 

C:\...\Options_Dialog.hpp:129: error: enclosing class of 'bool Options_Dialog::is_concurrency_selected() const' is not a literal type

Any thoughts on why?

Upvotes: 3

Views: 2825

Answers (1)

Johannes Schaub - litb
Johannes Schaub - litb

Reputation: 506837

It means your class is not a literal type... This program is invalid, because Options is not a literal class type. But Checker is a literal type.

struct Checker {
  constexpr bool isChecked() {
    return false;
  }
};

struct Options {
  Options(Checker *ConcurrentGBx)
    :ConcurrentGBx(ConcurrentGBx)
  { }

  constexpr bool is_concurrency_selected()const
  {
      //GBx is a groupbox with checkbox
      return ConcurrentGBx->isChecked();
  }

  Checker *ConcurrentGBx;
};

int main() {
  static Checker c;
  constexpr Options o(&c);
  constexpr bool x = o.is_concurrency_selected();
}

Clang prints

test.cpp:12:18: error: non-literal type 'Options' cannot have constexpr members
    constexpr bool is_concurrency_selected()const
                   ^
test.cpp:7:8: note: 'Options' is not literal because it is not an aggregate and has no constexpr constructors other than copy or move constructors
    struct Options {

If you fix this and make the Options constructor constexpr, my example snippet compiles. Similar things may apply to your code.

You appear to not understand what constexpr means. I recommend reading a book about it (if such a book exists already, anyway).

Upvotes: 6

Related Questions