CODEWITHSUNDEEP
ruby-on-railsrubyarraysenumeration
ere
ere

Reputation: 1779

ruby sort array of an array

I'm having a problem figuring out how I can sort an array of an array. Both arrays are straight forward and I'm sure it's quite simple, but I can't seem to figure it out.

Here's the array:

[["happy", 1], ["sad", 2], ["mad", 1], ["bad", 3], ["glad", 12]]

I want to sort it by the integer value of the inner array which is a value of how many times the word has occurred, biggest number first.

Upvotes: 13

Views: 11314

Answers (4)

nolith
nolith

Reputation: 613

sort can be used with a block.

a = [["happy", 1], ["sad", 2], ["mad", 1], ["bad", 3], ["glad", 12]]
a.sort { |o1, o2| o1[1] <=> o2[1] }
#=> [["happy", 1], ["mad", 1], ["sad", 2], ["bad", 3], ["glad", 12]]

Upvotes: 2

Waynn Lue
Waynn Lue

Reputation: 11375

This should do what you want.

a = [["happy", 1], ["sad", 2], ["mad", 1], ["bad", 3], ["glad", 12]]
a.sort {|x,y| y[1] <=> x[1]}

Upvotes: 1

Estanislau Trepat
Estanislau Trepat

Reputation: 598

Using the Array#sort method:

ary = [["happy", 1], ["sad", 2], ["mad", 1], ["bad", 3], ["glad", 12]]
ary.sort { |a, b| b[1] <=> a[1] }

Upvotes: 1

Edu
Edu

Reputation: 1969

Try either:

array = [["happy", 1], ["sad", 2], ["mad", 1], ["bad", 3], ["glad", 12]]
sorted = array.sort {|a,b| a[1] <=> b[1]}

Or:

array = [["happy", 1], ["sad", 2], ["mad", 1], ["bad", 3], ["glad", 12]]
sorted = array.sort {|a,b| b[1] <=> a[1]}

Depending if you want ascending or descending.

Upvotes: 34

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