CODEWITHSUNDEEP
javascriptjqueryjsonp
zbug
zbug

Reputation: 1043

JSONP function call issue

i set up a webservice thats cross domain and needs to be contacted via json with padding on a simple jquery codeline like this, i am successfull getting back json data.

$.getJSON("http://server/series/hist?jsonp=?", function(data){
 console.log(data);
});

the webservice, will wrap the result in a function, whenever "jsonp" exists within in the url. for those cases i used a default function name like: 

myfunction({"a":1})

jquery helps me out here, and trys to call the function, that isnt existing ("myfunction()"). what i am trying to achieve instead is a simple call of the callback function (see above), to handle the data locally.

can you point me in the right direction?

thank you

Upvotes: 0

Views: 369

Answers (1)

Quentin
Quentin

Reputation: 943510

I'm not quite sure what your problem actually is, but:

Interpretation 1

Assuming that by "locally" you mean "without using a callback":

That is impossible. JSON-P cannot work synchronously as it depends on the addition of a <script> element (which won't be processed until the current function has finished executing).

Interpretation 2

Assuming that by that isnt existing ("myfunction()") you mean "Your webservice always uses the function name myfunction:

Fix the webservice. jsonp=? means "Randomly generate a function name and pass it as the jsonp parameter.

The webservice must use that parameter to determine the function name used, and not use a fixed value such as myfunction.

Interpretation 3

You don't want to use JSON-P as the input, but to call your anonymous function directly.

You can't. It isn't stored anywhere you can access it. You have to rewrite your code so it isn't passed directly to getJSON:

function myFunction(data){
  console.log(data);
}

$.getJSON("http://server/series/hist?jsonp=?", myfunction); 
myfunction({"a":1})

Upvotes: 3

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