CODEWITHSUNDEEP
javascriptjqueryjsonjsonp
Lukas
Lukas

Reputation: 3

Requesting invalid JSON file using JSONP

I'm requesting JSON file which has an invalid structure: 

{}&&{
    "result": {
        "data": "01",
        "id": "02"
    }
}

I can't change JSON. It's on external server. Firebug returns syntax error pointing to the && characters.

What should I do to get this invalid JSON?

My script:

<script src="jquery.js"></script>
<script type="text/javascript">
$(document).ready(function() {      
$.ajax({
url:"http://different-domain.com",
dataType: 'JSONP',
success: parseJSON
function parseJSON(data){
// do stuff with json
}
});
</script>

Upvotes: 0

Views: 1422

Answers (3)

Paul Rumkin
Paul Rumkin

Reputation: 6873

You can use complete not a success. Than you could get RAW response before error comes. Then you can substr invalid chars while not to got parsed JSON:

$.ajax({
url:"http://different-domain.com",
dataType: 'JSONP',
complete: function(xhr){

    var raw= xhr.responseText
      , json
      , err
      ;

    while(raw.length && err)
    {
      // rewind state
      err= false;
      try {
        //parse JSON
        json= parseJSON(raw);
      }
      catch (e)
      {
        // Mark loop as invalid
        err= true;
      }

      // Get out if json is valid and parsed
      if (!err) break;

      // If loop is not broken try another one time: cut one char from invalid json and go on.
      raw= raw.substr(1);
    }

    if (!err)
    {
      console.log('YAPPPEEEEE :)');
    }
    else
    {
      console.log('NOPE :(');
    }
}

Upvotes: 1

bobince
bobince

Reputation: 536369

The {}&& prefix is chaff designed precisely to stop anyone outside different-domain.com from accessing the data. See this question for the background.

If you want a external interface so you can interact from outside the Same Origin Policy, you will have to get different-domain.com to change their script so that it supports the JSONP callback interface.

Upvotes: 2

maxedison
maxedison

Reputation: 17553

Looks like you want to remove the && and anything that comes before it. Assuming that this is always the case, do the following in the success handler of the $.ajax() method:

succes: function(data){
    var goodJSON = data.slice(4);
    var myObject = $.parseJSON(goodJSON);
}

myObject will now hold the fully parsed JSON.

Upvotes: 0

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