Reputation: 271
The question is the same as here, but in R. I have a matrix and a vector such that
length(vec) == nrow(mat)
How do i get a vector such that
v[i] == mat[v[i],i]
I tried to achieve this by using logical matrix:
>a = matrix(runif(12),4,3)
a
[,1] [,2] [,3]
[1,] 0.6077585 0.5354680 0.2802681
[2,] 0.2596180 0.6358106 0.9336301
[3,] 0.5317069 0.4981082 0.8668405
[4,] 0.6150885 0.5164009 0.5797668
> sel = col(a) == c(1,3,2,1)
> sel
[,1] [,2] [,3]
[1,] TRUE FALSE FALSE
[2,] FALSE FALSE TRUE
[3,] FALSE TRUE FALSE
[4,] TRUE FALSE FALSE
> a[sel]
[1] 0.6077585 0.6150885 0.4981082 0.9336301
It selects right elements but messes up the order. I thought of using mapply
either, but i don't know how to make it iterate through rows, like in apply
.
upd: @gsk3 suggested to use as.list(as.data.frame(t(a)))
this works. But still i would like to know if there is a more vectorized way, without lists.
Upvotes: 2
Views: 2039
Reputation: 4795
I am not 100% sure I understand your question, but it seems like this may be close?
> b=c(1,3,2,1)
> i=cbind(1:nrow(a),b)
> a[i]
Upvotes: 7