Reputation: 30568
Here is the code:
public static void main(String[] args) {
SocketWorker worker = null;
MyIOConsole mio = null;
try {
portNumber = 2012;
worker = new SocketWorker();
worker.assignPort(portNumber);
mio = new MyIOConsole();
mio.assignObject(worker);
Thread b = new Thread(mio);
b.start();
worker.run();
} catch (IOException e) {
e.printStackTrace();
}finally{
mio.applicationQuit();
}
}
The SocketWorker is simply a socket, listening the port 2012, and the MyIOConsole, will accept user command,
public class MyConsoleIO implements Runnable {
SocketWorker o;
static BufferedReader reader;
public void assignObject(Object o) {
reader = new BufferedReader(new InputStreamReader(System.in));
this.o = (SocketWorker) o;
}
@Override
public void run() {
String inputString = null;
System.out.println("Press 'q' to kill to program");
try {
inputString = reader.readLine();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
if (inputString.equalsIgnoreCase("q")) {
this.applicationQuit();
}
}
public void applicationQuit(){
this.o.stopWorking();
System.exit(0);
}
}
But when the Socket got the exception, even I catch them, the code
mio.applicationQuit();
keep run. I don't want that, I just want when the user close or crashed the application, the socket will close and quit. How can I solve it?
Upvotes: 0
Views: 113
Reputation: 7706
Add the following. The run method will be called as the JVM is exiting.
Runtime.getRuntime().addShutdownHook(new Thread() {
public void run(){
// cleanup code before JVM exit goes here.
}
});
Upvotes: 2