CODEWITHSUNDEEP
android
Programmer
Programmer

Reputation: 5400

Android URL to Uri

I have to change URL to URI, please guide me how can I change it.

I have tried a lot, but not getting the solution. Any help is appreciated. I can also attach code snippet if required.

Upvotes: 90

Views: 107813

Answers (5)

Tolgahan Albayram
Tolgahan Albayram

Reputation: 31

In Kotlin you can use this code snippet:

            val uri = Uri.parse("http://www.stackoverflow.com")

Upvotes: 2

Walied Abdulaziem
Walied Abdulaziem

Reputation: 399

var url = "http://10.0.2.2:8080/(mymobileapp)/login.php";

var response = await http.post(Uri.parse(url), body: data);

Upvotes: 0

Samir Mangroliya
Samir Mangroliya

Reputation: 40406

We can parse any URL using Uri.parse(String) method.

Code Snippet :

Uri uri =  Uri.parse( "http://www.stackoverflow.com" );

Upvotes: 126

Sparky
Sparky

Reputation: 8477

final String myUrlStr = "xyz";
URL url;
Uri uri;
try {
    url = new URL(myUrlStr);
    uri = Uri.parse( url.toURI().toString() );
} catch (MalformedURLException e1) {
    e1.printStackTrace();
} catch (URISyntaxException e) {
    e.printStackTrace();
}

Upvotes: 35

Mr H
Mr H

Reputation: 5304

This is my 2 Cents , it could help someone else.

The standard URL Parsing might not be good idea if you have variables passed to the URL as Query 

String your_url_which_is_not_going_to_change = "http://stackoverflow.com/?q="
String your_query_string = "some other stuff"
String query = null;

try {
  query = URLEncoder.encode(your_query_string, "utf-8");
} catch (UnsupportedEncodingException e) {
  // TODO Auto-generated catch block
  e.printStackTrace();
}

String url = your_url_which_is_not_going_to_change + query;

URL input = new URL(url);
etc... .

Hope it helps.

H.

Upvotes: 1

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