David
David

Reputation: 4007

Android sqlite cursor query

I'm following the http://www.vogella.de/articles/AndroidSQLite/article.html tutorial. I am now trying to change the system so there is not just field 'comment' but rather field 'item' and 'price'.

Now that I have 2 Coloums rather then one the cursor seems to be causing the app to crash! For example here is the code below:

        public List<Item> getAllItems() {
            List<Item> items = new ArrayList<Item>();
            Cursor cursor = database.query(MySQLiteHelper.TABLE_ITEMS,
                    allColumns, null, null, null, null, null);
            cursor.moveToFirst();

            while (!cursor.isAfterLast()) {
                Item item = cursorToItem(cursor);
                items.add(item);
                cursor.moveToNext();
            }
            // Make sure to close the cursor
            cursor.close();
            return items;
        }

        private Item cursorToItem(Cursor cursor) {
            Item item = new Item();
            item.setId(cursor.getLong(0));
            item.setItem(cursor.getString(1));
            item.setPrice(cursor.getString(2));
            return item;
        }

LINE :

 Cursor cursor = database.query(MySQLiteHelper.TABLE_ITEMS,
                    allColumns, null, null, null, null, null);

Is what is causing the error, I believe it has something to do with the fact that I have an additional column. can someone please tell me how to edit this line to get it to work, I have tried but don't understand this cursor query.

EDIT: By replacing allcolumns with null it ran. But now its crashing on:

public Item createItem(String item, String price) {
        ContentValues values = new ContentValues();
        values.put(MySQLiteHelper.COLUMN_ITEM, item);
        values.put(MySQLiteHelper.COLUMN_PRICE, price);
        long insertId = database.insert(MySQLiteHelper.TABLE_ITEMS, null,
                values);
        // To show how to query
        Cursor cursor = database.query(MySQLiteHelper.TABLE_ITEMS,
                allColumns, MySQLiteHelper.COLUMN_ID + " = " + insertId, null,
                null, null, null);
        cursor.moveToFirst();
        return cursorToItem(cursor);
    }

on line:

Cursor cursor = database.query(MySQLiteHelper.TABLE_ITEMS,
                allColumns, MySQLiteHelper.COLUMN_ID + " = " + insertId, null,
                null, null, null);

Here is the MySQLHelper.js:

package nupos.nupay.app;

import android.content.Context;
import android.database.sqlite.SQLiteDatabase;
import android.database.sqlite.SQLiteOpenHelper;
import android.util.Log;

public class MySQLiteHelper extends SQLiteOpenHelper {

public static final String TABLE_ITEMS = "items";
public static final String COLUMN_ID = "_id";
public static final String COLUMN_ITEM = "item";
public static final String COLUMN_PRICE = "price";

private static final String DATABASE_NAME = "items_test.db";
private static final int DATABASE_VERSION = 1;

// Database creation sql statement
private static final String DATABASE_CREATE = "create table "
        + TABLE_ITEMS + "( " + COLUMN_ID
        + " integer primary key autoincrement, " + COLUMN_ITEM
        + " text not null," + COLUMN_PRICE
        +"  text not null);";

public MySQLiteHelper(Context context) {
    super(context, DATABASE_NAME, null, DATABASE_VERSION);
}

@Override
public void onCreate(SQLiteDatabase database) {
    database.execSQL(DATABASE_CREATE);
}

@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
    Log.w(MySQLiteHelper.class.getName(),
            "Upgrading database from version " + oldVersion + " to "
                    + newVersion + ", which will destroy all old data");
    db.execSQL("DROP TABLE IF EXISTS " + TABLE_ITEMS);


    onCreate(db);
}

 }

Edit: The issue was the database was created initially without one of the fields.

Upvotes: 1

Views: 2831

Answers (1)

Gangnus
Gangnus

Reputation: 24464

IMHO, allColumns doesn't sit with the MySQLiteHelper.TABLE_ITEMS definition. Put here declarations and current values of all participying objects.

One more possibility - database object is not initialized properly and is null at the moment. You should check for such situations.

Upvotes: 1

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