Reputation: 18747
I am having some issues in dealing with zip files on Mac OS X 10.7.3.
I am receiving a zip file from a third party, which I have to process. My code is using ZipInputStream to do this. This code has been used several times before, without any issue but it fails for this particular zip file. The error which I get is as follows:
java.util.zip.ZipException: invalid compression method
at java.util.zip.ZipInputStream.read(ZipInputStream.java:185)
at java.util.zip.InflaterInputStream.read(InflaterInputStream.java:105)
at org.apache.xerces.impl.XMLEntityManager$RewindableInputStream.read(Unknown Source)
at org.apache.xerces.impl.XMLEntityManager.setupCurrentEntity(Unknown Source)
at org.apache.xerces.impl.XMLVersionDetector.determineDocVersion(Unknown Source)
at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source)
at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source)
at org.apache.xerces.parsers.XMLParser.parse(Unknown Source)
at org.apache.xerces.parsers.AbstractSAXParser.parse(Unknown Source)
I googled about it and I can see that there are some issues with ZipInputStream, e.g. this one.
I have also found some related questions on Stackoverflow, e.g. this one. But there is no proper, accepted/acceptable answer.
I have a couple questions:
Note that as with some users, if I unzip the file on my local machine and re-zip it, it works perfectly fine.
EDIT 1:
The file which I am getting is in .zip
format, I don't know which OS/utility program they are using to compress it. On my local machine I am using the built-in zip utility which comes with Mac OS X.
Upvotes: 4
Views: 11971
Reputation: 2134
API JAVADOC : THIS is what actually compresses your file ( Updated Feb 2021 note, the oracle provided link expired, Duke University (no affiliation) however has the antiquated 1.4 javadoc available) : https://www2.cs.duke.edu/csed/java/jdk1.4.2/docs/api/java/util/zip/ZipEntry.html
per that interface, you are able to get and set compression methods ( getCompression()
and setCompression(int)
, respectively).
good luck!
Upvotes: 1
Reputation: 19027
I'm using the following code in Java on my Windows XP OS to zip folders. It may at least be useful to you as a side note.
//add folder to the zip file
private void addFolderToZip(String path, String srcFolder, ZipOutputStream zip) throws Exception
{
File folder = new File(srcFolder);
//check the empty folder
if (folder.list().length == 0)
{
System.out.println(folder.getName());
addFileToZip(path , srcFolder, zip,true);
}
else
{
//list the files in the folder
for (String fileName : folder.list())
{
if (path.equals(""))
{
addFileToZip(folder.getName(), srcFolder + "/" + fileName, zip,false);
}
else
{
addFileToZip(path + "/" + folder.getName(), srcFolder + "/" + fileName, zip,false);
}
}
}
}
//recursively add files to the zip files
private void addFileToZip(String path, String srcFile, ZipOutputStream zip,boolean flag)throws Exception
{
//create the file object for inputs
File folder = new File(srcFile);
//if the folder is empty add empty folder to the Zip file
if (flag==true)
{
zip.putNextEntry(new ZipEntry(path + "/" +folder.getName() + "/"));
}
else
{
//if the current name is directory, recursively traverse it to get the files
if (folder.isDirectory())
{
addFolderToZip(path, srcFile, zip); //if folder is not empty
}
else
{
//write the file to the output
byte[] buf = new byte[1024];
int len;
FileInputStream in = new FileInputStream(srcFile);
zip.putNextEntry(new ZipEntry(path + "/" + folder.getName()));
while ((len = in.read(buf)) > 0)
{
zip.write(buf, 0, len); //Write the Result
}
}
}
}
//zip the folders
private void zipFolder(String srcFolder, String destZipFile) throws Exception
{
//create the output stream to zip file result
FileOutputStream fileWriter = new FileOutputStream(destZipFile);
ZipOutputStream zip = new ZipOutputStream(fileWriter);
//add the folder to the zip
addFolderToZip("", srcFolder, zip);
//close the zip objects
zip.flush();
zip.close();
}
private boolean zipFiles(String srcFolder, String destZipFile) throws Exception
{
boolean result=false;
System.out.println("Program Start zipping the given files");
//send to the zip procedure
zipFolder(srcFolder,destZipFile);
result=true;
System.out.println("Given files are successfully zipped");
return result;
}
In this code, you need to invoke the preceding method zipFiles(String srcFolder, String destZipFile)
by passing two parameters. The first parameter indicates your folder to be zipped and the second parameter destZipFile
indicates your destination zip folder.
The following code is to unzip a zipped folder.
private void unzipFolder(String file) throws FileNotFoundException, IOException
{
File zipFile=new File("YourZipFolder.zip");
File extractDir=new File("YourDestinationFolder");
extractDir.mkdirs();
ZipInputStream inputStream = new ZipInputStream(new FileInputStream(zipFile));
try
{
ZipEntry entry;
while ((entry = inputStream.getNextEntry()) != null)
{
StringBuilder sb = new StringBuilder();
sb.append("Extracting ");
sb.append(entry.isDirectory() ? "directory " : "file ");
sb.append(entry.getName());
sb.append(" ...");
System.out.println(sb.toString());
File unzippedFile = new File(extractDir, entry.getName());
if (!entry.isDirectory())
{
if (unzippedFile.getParentFile() != null)
{
unzippedFile.getParentFile().mkdirs();
}
FileOutputStream outputStream = new FileOutputStream(unzippedFile);
try
{
byte[] buffer = new byte[1024];
int len;
while ((len = inputStream.read(buffer)) != -1)
{
outputStream.write(buffer, 0, len);
}
}
finally
{
if (outputStream != null)
{
outputStream.close();
}
}
}
else
{
unzippedFile.mkdirs();
}
}
}
finally
{
if (inputStream != null)
{
inputStream.close();
}
}
}
Upvotes: 1