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Neil
Neil

Reputation: 2058

Change button properties with loop? Xcode

I would like tone able to cut these lines down:

[button0 addGestureRecognizer:longPress];
[button1 addGestureRecognizer:longPress];
[button2 addGestureRecognizer:longPress];
[button3 addGestureRecognizer:longPress];
[button4 addGestureRecognizer:longPress];
[button5 addGestureRecognizer:longPress];
[button6 addGestureRecognizer:longPress];
[button7 addGestureRecognizer:longPress];
[button8 addGestureRecognizer:longPress];
[button9 addGestureRecognizer:longPress];

etc.. all the way to 36!!

Possibly with a loop? But i'm not sure how to do this.

Thanks, Regards.

Upvotes: 1

Views: 2031

Answers (2)

sch
sch

Reputation: 27506

You can assign a tag to each button and loop through the buttons using the method viewWithTag.

for (int i = 0; i < 36; i++) {
    UIButton *button = [self.view viewWithTag:i];
    UILongPressGestureRecognizer *longPress = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(handleLongPress:)];
    [button addGestureRecognizer:longPress];
}

The following screenshot shows where to assign the tag for each button in Interface Builder.

enter image description here

If you have setup IBOutlets for the buttons, you can obtain them using valueForKey: and without the tag:

for (int i = 0; i < 36; i++) {
    NSString *key = [NSString stringWithFormat:@"button%d", i];
    UIButton *button = [self valueForKey:key];
    UILongPressGestureRecognizer *longPress = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(handleLongPress:)];
    [button addGestureRecognizer:longPress];
}

Upvotes: 6

jonkroll
jonkroll

Reputation: 15722

Put your buttons in an array and use fast enumeration to iterate over them.

NSArray *buttons = [NSArray arrayWithObjects:button0, button1, button2, button3, button4, button5, button6, button7, button8, button9, nil];

for (UIButton *button in buttons) {
    [button addGestureRecognizer:longPress];
}

Upvotes: 2

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