CODEWITHSUNDEEP
pythondictionary
user1182090
user1182090

Reputation: 301

how can i skip blank values in dict

I have a dict:

x = {'a': {'p': 'in-gaap', 'r': 'inr', 'dec': 0},
     'b': {'p': 'in-ca', 'r': 'inr', 'dec': 0},
     'c': {'p': 'in-gaap', 'r': '', 'dec': ''},
     'd': {'p': 'in-gaap', 'r': 'inr', 'dec': 0}}

i am using this code to skip blank values:

for k,v in x.iteritems():
    if d[k]['r'] == '' and d[k]['dec'] == '':
        print k, x[k]['p']
    else:                
        print x[k]['p'], x[k]['r'], x[k]['dec']

But the output is:

a,in-gaap
b,in-ca
c-in-gaap
d-in-gaap

it's not executing condition properly, it is printing all values

And I also tried using this code

for k,v in x.iteritems():
    obj = re.match('\w+', x[k]['p'])
    obj1 = re.match('\w+', x[k]['q'])
    if not obj1 and obj2:
        print k, x[k]['p']
    else:                
        print x[k]['p'], x[k]['r'], x[k]['dec']

But output is same as above.

Actually the blank values of dict contains "\n", '', etc. and some non-ascii characters so I tried using re, but it's not executing properly.

Upvotes: 0

Views: 1160

Answers (2)

mshsayem
mshsayem

Reputation: 18028

Not sure if this is what you want:

for k,v in x.iteritems():
    if not v['r'] and not v['dec']:
        print k,v['p']
    else:
        print v['p'],v['r'],v['dec']

Outputs:

in-gaap inr 0
c in-gaap
in-ca inr 0
in-gaap inr 0

Upvotes: 0

bos
bos

Reputation: 6555

In your first code you are referring to a dict named d, which we have no idea what it is. If I rename your dict to d instead of x, I get this output:

>>> ## working on region in file /usr/tmp/python-30572oWE...
in-gaap inr 0
c in-gaap
in-ca inr 0
in-gaap inr 0

Which seems to be what you are looking for.

Upvotes: 4

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