Reputation: 53
Heres my error...
"In constructor 'NumGame::NumGame(int&)': error: no matching function for call to 'Category::Category()'"
Ive looked at a few similar questions here but cant seem to find an answer. I have a base class Category and NumGame is inherited from it but wont compile.
class Category {
public:
void virtual selection(int&);
Category(int&);
virtual ~Category(){};
private:
int myRandNum;
};
Category::Category(int& a){
myRandNum = a;
}
void Category::selection(int& a){
cout << "I am NumGame version number... " << a << endl;
cout << "Now Im playing... " << myRandNum << endl;
}
class NumGame : public Category {
public:
void selection(int&);
NumGame(int&);
~NumGame(){};
private:
int myRandNum;
};
NumGame::NumGame(int& b){
myRandNum = b;
}
void NumGame::selection(int& b) {
}
Upvotes: 5
Views: 52564
Reputation: 206508
Reason for the error:
When you create an instance of derived class NumGame
the Base class Category
no argument constructor is called to create the Category
part of the object. Your class doesn't have one and the compiler complains about it.
Why the compiler did not synthesize the default constructor?
Once you provide any constructor for your class the compiler does not synthesize the constructor which does not take any argument for you, You have to provide that yourself if your code uses one.
Solutions:
There are two ways to avoid the error:
Call the appropriate available constructor in Base class Catoegory
subobject through Member Initializer list. This removes the scenario where your code uses a no argument constructor.
NumGame::NumGame(int& b) : Category(b)
{
}
OR
You need to provide a no argument constrcutor for Category
class yourself:
Category::Category()
{
}
Upvotes: 22
Reputation: 1499
in your NumGame
class you have to provide a call to constructor of base class. if you don t, compiler do it for you with default contructor : in your case Category()
that you don t have..
Upvotes: 0
Reputation: 40613
Category
does not have a default constructor, so you need to supply arguments when constructing the Category
base object of NumGame
:
NumGame::NumGame(int& b) :
Category(b)
{
myRandNum = b;
}
Upvotes: 9