CODEWITHSUNDEEP
jqueryplugins
Lee
Lee

Reputation: 750

Dynamically Use jQuery Options in Plugin

Not sure if I'm approaching this correctly ...

Basically I have a plugin structure along the lines of:

(function($){

$.fn.xxxxx = function(options) {

    var o = {
        widgets: 'a,b,c',
        a: {
            id: 'abc',
            title: 'ABC'
        },
        b: {
            id: 'def',
            title: 'DEF'
        },
        c: {
            id: 'ghi',
            title: 'GHI'
        }
    };

    var options = $.extend(o, options);

    return this.each(function(options){

        var myplugin = {
            init: function(){
                var x = o.widgets.split(',');
                $.each(x, function(i,v){
                    myplugin.widgets(i,v);
                });
            },
            widgets: function(i,v){

                var t = o.v.title ? '<h3>'+o.v.title+'</h3>' : '' ;

            }
        }
        myplugin.init();
    });
};

})(jQuery);

Is it possible to use the string values from the o.widgets option to then call one of the o.a, o.b, o.c options?

Basically the a, b or c would be passed to the widgets function and then used to assign the option value. The following is what I want it to do but it obviously doesnt work like that:

var t = o.v.title ? '<h3>'+o.v.title+'</h3>' : '' ;

Any help appreciated!

Upvotes: 0

Views: 52

Answers (2)

Salman Arshad
Salman Arshad

Reputation: 272066

You can do this:

var t = o['a'].title ? '<h3>' + o['a'].title + '</h3>' : '';

Which allows you to do this:

var v = 'a';
var t = o[v].title ? '<h3>' + o[v].title + '</h3>' : '';

Upvotes: 1

Richard Neil Ilagan
Richard Neil Ilagan

Reputation: 14747

Well, one of the nice things about Javascript in particular is that the following are equivalent:

foo.bar === foo['bar'];

So if you want to access o.a, you can access it via o['a']. Taking that further, you can fashion a function like the following:

function herp (opt) {
    return o[opt];
}

... and call it like var foo = herp('a'); or something.

Upvotes: 1

Related Questions