Reputation: 1645
I have a table:
<table id="Table">
<tr id="tr-1">
<td>1</td>
</tr>
<tr id="tr-2">
<td>2</td>
</tr>
<tr id="tr-3">
<td>3</td>
</tr>
<tr id="tr-4>
<td>4</td>
</tr>
<tr id="tr-5">
<td>5</td>
</tr>
</table
I have code that looks for the last <tr>
in that table
var ID = $("#Table tr:last").attr("id");
Now I want to find the id of the <tr>
that is two <tr>
's back from the ID that I collected. The answer would be <tr>
id="3". But what code would I write to get that answer?
Upvotes: 2
Views: 196
Reputation: 349252
Use the :nth-last-child
selector: http://jsfiddle.net/7QFDB/.
var ID = $("#Table tr:nth-last-child(2)").attr("id");
This selector is implemented in most modern browsers. For compatibility, this jQuery plugin can be used.
Upvotes: 5
Reputation: 171698
Can get the index()
of last row then use that to go any number of rows you want
var lastRowIndex= $("#Table tr:last").index();
var different_row= $("#Table tr").eq(lastRowIndex-2)
Upvotes: 1
Reputation: 18379
You can use prev()
twice:
var id = $("#Table tr:last").prev().prev().attr("id");
Upvotes: 1