Reputation: 64227
When c
map equals a function of a
map I can calculate it as
val a: Map[T, U] = ...
def f(aValue: U): V = ...
val c: Map[T, V] = a.map(f)
but what if c
map equals a function of both a
and b
as arguments? For example if a
, b
and c
are Map[String, Int]
and a c
values are to equal corresponding a
values raised to powers specified by corresponding b
values?
Upvotes: 0
Views: 709
Reputation: 7979
Something like this?
val a: Map[String, Int] = Map("a" -> 10, "b" -> 20)
val b: Map[String, Int] = Map("a" -> 2, "b" -> 3)
def f(a: Int, b: Int): Int = math.pow(a,b).toInt // math.pow returns a Double
val c = for {
(ak, av) <- a // for all key-value pairs from a
bv <- b.get(ak) // for any matching value from b
} yield (ak, f(av,bv)) // yield a new key-value pair that results from applying f
// c: scala.collection.immutable.Map[String,Int] = Map(a -> 100, b -> 8000)
Upvotes: 2
Reputation: 52691
Is this what you're after?
val a = Map('a -> 2, 'b -> 3)
val b = Map('a -> 4, 'b -> 5)
a.map{ case (k, aVal) => (k, aVal + b(k)) } // Map('a -> 6, 'b -> 8)
Upvotes: 1