Reputation: 33702
Why do you think the code below does not work? What would you change/add to make it work?
Any help is appreciated..
function TraceIt(message:String, num:int)
{
trace(message, num);
}
function aa(f:Function, ...args):void
{
bb(f, args);
}
aa(TraceIt, "test", 1);
var func:Function = null;
var argum:Array = null;
function bb(f:Function, ...args):void
{
func = f;
argum = args;
exec();
}
function exec()
{
func.apply(null, argum);
}
I get an ArgumentError (Error #1063):
Argument count mismatch on test_fla::MainTimeline/TraceIt(). Expected 2, got 1.
..so, the passed parameter (argum) fails to provide all passed arguments..
..Please keep the function structure (traffic) intact.. I need a solution using the same functions in the same order.. I have to pass the args to a variable and use them in the exec() method above..
regards
Upvotes: 2
Views: 7679
Reputation: 33702
Ok, here is the solution.. after breaking my head : )
function TraceIt(message:String, num:int)
{
trace(message, num);
}
function aa(f:Function=null, ...args):void
{
var newArgs:Array = args as Array;
newArgs.unshift(f);
bb.apply(null, newArgs);
}
aa(TraceIt, "test", 1);
var func:Function = null;
var argum:*;
function bb(f:Function=null, ...args):void
{
func = f;
argum = args as Array;
exec();
}
function exec():void
{
if (func == null) { return; }
func.apply(this, argum);
}
This way, you can pass arguments as variables to a different function and execute them..
Thanks to everyone taking the time to help...
Upvotes: 7
Reputation: 28250
Change your bb function to look like this:
function bb(f:Function, args:Array):void
{
func = f;
argum = args;
exec();
}
As you have it now, it accepts a variable number of arguments, but you are passing in an array(of the arguments) from aa.
Upvotes: 1
Reputation: 3936
When TraceIt() eventually gets called, it's being called with 1 Array parameter, not a String and int parameters.
You could change TraceIt() to:
function TraceIt(args:Array)
{
trace(args[0], args[1]);
}
Or you could change exec() to:
function exec()
{
func.apply(null, argum[0].toString().split(","));
}
...as it appears when you pass "test", 1, you end up with array whose first value is "test,1". This solution doesn't work beyond the trivial case, though.
Upvotes: 1