Reputation: 16656
I receive a char * buffer which have the lenght of 10. But I want to concat the whole content in my struct which have an variable char *.
typedef struct{
char *buffer;
//..
}file_entry;
file_entry real[128];
int fs_write(char *buffer, int size, int file) {
//every time this function is called buffer have 10 of lenght only
// I want to concat the whole text in my char* in my struct
}
Something like this :
real[i].buffer += buffer;
How can I do this in C ?
Upvotes: 13
Views: 40275
Reputation: 4290
I am not clear. Do you want:
real[0].buffer
, orreal[i].buffer
, orYou will need to allocate enough space for the copy of the buffer:
#include <stdlib.h>
//...
int size = 10+1; // need to allocate enough space for a terminating '\0'
char* buff = (char *)malloc(size);
if (buff == NULL) {
fprintf(stderr, "Error: Failed to allocate %d bytes in file: %s, line %d\n",
size, __FILE__, __LINE__ );
exit(1);
}
buff[0] = '\0'; // terminate the string so that strcat can work, if needed
//...
real[i].buffer = buff; // now buffer points at some space
//...
strncpy(real[i].buffer, buffer, size-1);
Upvotes: 0
Reputation: 7706
In general, do the following (adjust and add error checking as you see fit)
// real[i].buffer += buffer;
// Determine new size
int newSize = strlen(real[i].buffer) + strlen(buffer) + 1;
// Allocate new buffer
char * newBuffer = (char *)malloc(newSize);
// do the copy and concat
strcpy(newBuffer,real[i].buffer);
strcat(newBuffer,buffer); // or strncat
// release old buffer
free(real[i].buffer);
// store new pointer
real[i].buffer = newBuffer;
Upvotes: 13
Reputation: 224864
You can use strcat(3)
to concatenate strings. Make sure you have allocated enough space at the destination!
Note that just calling strcat()
a bunch of times will result in a Schlemiel the Painter's algorithm. Keeping track of the total length in your structure (or elsewhere, if you prefer) will help you out with that.
Upvotes: 4