ocinisme
ocinisme

Reputation: 301

JVM 104 : Stack OverFlow Error in Blackberry Simulator

I am getting this error in my program after adding few label and editfield, then passing the saved value to the other class.

It gave me StackOverFlow error when I pressed on the particular button, yet the class did not implements any Hashtable elements.

LongHashtable.get(long) line: 454

And this is the class I mentioned about.

public final class RSSMainScreen extends MainScreen implements FieldChangeListener{

RSSFeedList rfl = new RSSFeedList ();

String rssUrl1 = "http://kompas.feedsportal.com/c/33612/f/589626/index.rss";
String rssUrl2 = "http://feeds.gawker.com/lifehacker/full";
String rssUrl3 = rfl.x ;

ButtonField viewRSSButton = new ButtonField("Refresh");
ButtonField editRSSButton = new ButtonField("Settings");

DefaultHandler dh = new DefaultHandler();

public RSSMainScreen()
{       

    // Set the displayed title of the screen       
    HorizontalFieldManager hfm = new HorizontalFieldManager(HorizontalFieldManager.FIELD_HCENTER);

    setTitle("");

    viewRSSButton.setChangeListener(this);
    editRSSButton.setChangeListener(this);

    String[][] urlData1 = dh.getURLFromRSS(rssUrl1);
    String[][] urlData2 = dh.getURLFromRSS(rssUrl2);
    String[][] urlData3 = dh.getURLFromRSS(rssUrl3);


    add(new LabelField("KOMPAS"));
    add(new SeparatorField());

    for (int i = 0; i < urlData1.length; i++) 
    {
        String title = urlData1[0][i];
        String url = urlData1[1][i];
        add(new LinkLabel(title, url));
        add(new SeparatorField());
    }

    add(new LabelField("LIFEHACKER"));
    add(new SeparatorField());

    for (int i = 0; i < urlData2.length; i++) 
    {
        String title = urlData2[0][i];
        String url = urlData2[1][i];
        add(new LinkLabel(title, url));
        add(new SeparatorField());
    }

    add(new LabelField("CUSTOM"));
    add(new SeparatorField());

    for (int i = 0; i < urlData3.length; i++) 
    {
        String title = urlData3[0][i];
        String url = urlData3[1][i];
        add(new LinkLabel(title, url));
        add(new SeparatorField());
    }

    hfm.add(viewRSSButton);
    hfm.add(editRSSButton);

    this.add(hfm);
}

This it the class from where the String value will be passed.

May I know how to solve this issue?

public class RSSFeedList extends MainScreen implements FieldChangeListener {
RSSMainScreen rms = new RSSMainScreen();

ButtonField backButton = new ButtonField("Cancel and Back");
ButtonField saveButton = new ButtonField("Save");
BasicEditField thirdURL = new BasicEditField();

String x  = "";

protected RSSFeedList()
{
    HorizontalFieldManager hfm = new HorizontalFieldManager(HorizontalFieldManager.FIELD_HCENTER);

    backButton.setChangeListener(this);
    saveButton.setChangeListener(this);

    LabelField firstURLLabel = new LabelField("First RSS");
    LabelField firstURL = new LabelField(rms.rssUrl1);

    LabelField secondURLLabel = new LabelField("Second RSS");
    LabelField secondURL = new LabelField(rms.rssUrl2);

    LabelField thirdURLLabel = new LabelField("Third RSS (Editable)");

    hfm.add(firstURLLabel);
    hfm.add(new SeparatorField());
    hfm.add(firstURL);
    hfm.add(new SeparatorField());
    hfm.add(secondURLLabel);
    hfm.add(new SeparatorField());
    hfm.add(secondURL);
    hfm.add(new SeparatorField());
    hfm.add(thirdURLLabel);
    hfm.add(new SeparatorField());
    hfm.add(thirdURL);
    hfm.add(new SeparatorField());

    hfm.add(backButton);
    hfm.add(saveButton);

    this.add(hfm);
}

public void fieldChanged(Field field, int context) 
{
    if(field == backButton)
    {
        //screen = new RSSMainScreen();
    }
    else if(field == saveButton)
    {
        x = thirdURL.getText().toString();
        //screen = new RSSMainScreen();
        UiApplication.getUiApplication().pushScreen(new RSSMainScreen());
    }

}}

Thanks!

Upvotes: 0

Views: 561

Answers (1)

user784540
user784540

Reputation:

Seems that you run out of memory/stack resources on your device at the runtime.

When you press a button you compose (a quite complex) screen and push it on the screen stack. And when a button on the new screen is pressed, then you produce new object and push this new screen to the stack.

This is not a good approach at all. Instead of that consider having one screen and update its content via change event. Do not produce new screens, update content of the existing one.

Upvotes: 1

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