dimo414
dimo414

Reputation: 48814

How To Identify The Requested Page In PHP

Is there any easy way to identify the file initially handling the request, ignoring get arguments and handling (at least basic) mappings like / to /index.php?

Ideally what I'm looking for is something like $_SERVER['REQUEST_URI'], except it returns the same value regardless of the get arguments and that value is the file requested, not the URI, nor the currently executing file ($_SERVER['PHP_SELF']). In other words, a $_SERVER['REQUESTED_FILE'] or something. I haven't seen anything like that. Does it exist, or do I need to write something manually?

Update Here are some example URLs paired with what I would like the result to be:

example.com/mypage.php       : /mypage.php
example.com/                 : /index.php
example.com/foo/?hello=world : /foo/index.php

And these return values are true even in included files. See my answer below before answering, I think I've found what I was looking for.

Upvotes: 17

Views: 34856

Answers (5)

Somnath
Somnath

Reputation: 352

Go get file name from the requested URL use following code.

basename($_SERVER['URL']);
basename($_SERVER['REQUEST_URI']);
basename($_SERVER['SCRIPT_NAME']);
basename($_SERVER['SCRIPT_FILENAME']);
basename($_SERVER['REQUEST_URI']);
basename($_SERVER['PATH_TRANSLATED']);
basename($_SERVER['PHP_SELF']);

use any one all all of those in the nested if condition so you will not miss file name any how.

Upvotes: 3

Ashman Malhotra
Ashman Malhotra

Reputation: 1

Its very old question and not very clear too. What I understood is that you want to know which page is sending request GET/POST. This can be implemented by:

$_SERVER['HTTP_REFERER']

Now, to get the actual page name, write like: = basename($_SERVER['HTTP_REFERER']);

This will solve you concern.

Upvotes: -1

dimo414
dimo414

Reputation: 48814

I decided to test it out myself. The $_SERVER['SCRIPT_NAME'] variable serves up the path to the requested file, even if it's an index file, and without get parameters or anything else. The PHP documentation states this contains the path of the file, but it seems to be relative to the document root, just like PHP_SELF, but without the security vulnerability.

Here is the code I used to test this: https://gist.github.com/dimo414/5484870

The output when requesting example.com/?foo=bar:

__FILE__:               /var/www/index.php
PHP_SELF:               /index.php
SCRIPT_NAME:            /index.php
REQUEST_URI:            /?foo=bar
parse_url(REQUEST_URI): /


__FILE__:               /var/www/pathtest.php
PHP_SELF:               /index.php
SCRIPT_NAME:            /index.php
REQUEST_URI:            /?foo=bar
parse_url(REQUEST_URI): /

And the output when requesting example.com/index.php/<strong>XSS</strong>:

__FILE__:               /var/www/index.php
PHP_SELF:               /index.php/XSS # note the XSS exploit (this is bold in browser)
SCRIPT_NAME:            /index.php     # No exploit here
REQUEST_URI:            /index.php/%3Cstrong%3EXSS%3C/strong%3E
parse_url(REQUEST_URI): /index.php/%3Cstrong%3EXSS%3C/strong%3E


__FILE__:               /var/www/pathtest.php
PHP_SELF:               /index.php/XSS
SCRIPT_NAME:            /index.php
REQUEST_URI:            /index.php/%3Cstrong%3EXSS%3C/strong%3E
parse_url(REQUEST_URI): /index.php/%3Cstrong%3EXSS%3C/strong%3E

As you can see, $_SERVER['SCRIPT_NAME'] always gives back the file that originally handled the request, i.e. the file in the URL, without any XSS risks.

Upvotes: 29

Jet
Jet

Reputation: 1171

  1. parse_url($_SERVER['REQUEST_URI']) and then pathinfo($path) to get requested filename
  2. $_SERVER['PHP_SELF'] to get real filename
  3. $_SERVER['SCRIPT_NAME'] to get real filename

Upvotes: 0

Oli
Oli

Reputation: 239810

$_SERVER['PHP_SELF']

Should return the actual script. But there are various methods.

I had a better link to a matrix of all the various file-related environment variables but I can't find it. I'll edit if it turns up.

Edit: I found a nice SO thread that details the differences between them.

Upvotes: 6

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