stackoverflow
Reputation: 19444
MySQL How do I create this subquery?
I have the following tables
Table Farm
+---------+--------+-------------------+-----------+------------+
| FARM_ID |Stock_ID| FARM_TITLE | Size | FARM_VALUE |
+---------+--------+-------------------+-----------+------------+
| 2 | 1 | AgriZone | M | 202 |
| 3 | 1 | Cow Mill | L | 11 |
| 4 | 2 | Beef Farm | H | 540 |
| 5 | 2 | CattleOne | M | 1080 |
| 6 | 2 | FarmOne | L | 455 |
| 7 | 3 | Perdue | H | 333 |
| 8 | 4 | Holstein | M | 825 |
| 10 | 1 | Dotterers | H | 98 |
+---------+--------+-------------------+-----------+------------+
Table Gate
+---------+---------+------------+
| GATE_ID | FARM_ID | FARM_VALUE |
+---------+---------+------------+
| 1 | 2 | 0 |
| 1 | 3 | 0 |
| 1 | 4 | 540 |
| 2 | 4 | 550 |
| 3 | 4 | 560 |
| 4 | 4 | 570 |
| 5 | 4 | 580 |
| 6 | 4 | 590 |
| 1 | 5 | 1080 |
| 2 | 5 | 1100 |
| 3 | 5 | 1120 |
| 4 | 5 | 1140 |
| 5 | 5 | 1160 |
| 6 | 5 | 1180 |
| 1 | 6 | 455 |
| 2 | 6 | 536 |
| 3 | 6 | 617 |
| 4 | 6 | 698 |
| 5 | 6 | 779 |
| 6 | 6 | 860 |
| 1 | 7 | 0 |
| 1 | 8 | 0 |
| 1 | 10 | 0 |
+---------+---------+------------+
Table Origin
+--------+----------+
| ORI_ID | ORI_NAME |
+--------+----------+
| 1 | US |
| 2 | CA |
| 3 | MX |
+--------+----------+
Table Stock
+--------+--------+-------------------+
|Stock_ID| ORI_ID | Stock_TITLE |
+--------+--------+-------------------+
| 1 | 1 | P1 |
| 2 | 2 | P3 |
| 3 | 3 | Q4 |
| 4 | 3 | B3 |
+--------+--------+-------------------+
Table Results
+-----------+---------+---------+------------+------------+
| RESULT_ID | FARM_ID | GATE_ID | FARM_VALUE | Score% |
+-----------+---------+---------+------------+------------+
| 1 | 7 | 1 | 333 | 100 |
| 2 | 8 | 1 | 825 | 100 |
| 3 | 6 | 1 | 455 | 40 |
| 4 | 6 | 2 | 536 | 0 |
| 5 | 6 | 3 | 617 | 0 |
| 6 | 6 | 4 | 698 | 100 |
| 7 | 6 | 5 | 779 | 0 |
| 8 | 6 | 6 | 860 | 10 |
| 9 | 4 | 1 | 540 | 100 |
| 10 | 4 | 2 | 550 | 90 |
| 11 | 4 | 3 | 560 | 0 |
| 12 | 4 | 4 | 570 | 100 |
| 13 | 4 | 5 | 580 | 10 |
| 14 | 4 | 6 | 590 | 0 |
| 15 | 5 | 1 | 1080 | 0 |
| 16 | 5 | 2 | 1100 | 0 |
| 17 | 5 | 3 | 1120 | 0 |
| 18 | 5 | 4 | 1140 | 50 |
| 19 | 5 | 5 | 1160 | 0 |
| 20 | 5 | 6 | 1180 | 100 |
| 21 | 3 | 1 | 11 | 100 |
| 22 | 10 | 1 | 98 | 90 |
| 23 | 2 | 1 | 202 | 100 |
+-----------+---------+---------+------------+------------+
Annotated Result table: Same as above ^
+-----------+---------+---------+------------+------------+
| RESULT_ID | FARM_ID | GATE_ID | FARM_VALUE | Score% |
+-----------+---------+---------+------------+------------+
+-----------+---------+---------+------------+------------+
| 1 | 7 | 1 | 333 | 100 | <--|H-Case {H}
+-----------+---------+---------+------------+------------+
+-----------+---------+---------+------------+------------+
| 2 | 8 | 1 | 825 | 100 | <--|M-Case {M}
+-----------+---------+---------+------------+------------+
+-----------+---------+---------+------------+------------+
| 3 | 6 | 1 | 455 | 40 |
| 4 | 6 | 2 | 536 | 0 |
| 5 | 6 | 3 | 617 | 0 |
| 6 | 6 | 4 | 698 | 100 | <--|L
| 7 | 6 | 5 | 779 | 0 | |
| 8 | 6 | 6 | 860 | 10 | |
+-----------+---------+---------+------------+------------+ |
| 9 | 4 | 1 | 540 | 100 | |
| 10 | 4 | 2 | 550 | 90 | |
| 11 | 4 | 3 | 560 | 0 | |
| 12 | 4 | 4 | 570 | 100 | <--+M-case {H,M,L}
| 13 | 4 | 5 | 580 | 10 | |
| 14 | 4 | 6 | 590 | 0 | |
+-----------+---------+---------+------------+------------+ |
| 15 | 5 | 1 | 1080 | 0 | |
| 16 | 5 | 2 | 1100 | 0 | |
| 17 | 5 | 3 | 1120 | 0 | |
| 18 | 5 | 4 | 1140 | 50 | <--|H
| 19 | 5 | 5 | 1160 | 0 |
| 20 | 5 | 6 | 1180 | 100 |
+-----------+---------+---------+------------+------------+
+-----------+---------+---------+------------+------------+
| 21 | 3 | 1 | 11 | 100 | <--|L
| 22 | 10 | 1 | 98 | 90 | <--+H-case {H,M,L}
| 23 | 2 | 1 | 202 | 100 | <--|M
+-----------+---------+---------+------------+------------+
Computations required:
- Type can have only three values at most: {H, M, L};
- When all values are present, they are graded as followed: H=70 M=20 L=10
ALL unique casese are
Case {H,M} : H=80 M=20
- Case {M,L} : M=60 L=40
- Case {H,L} : H=90 L=10
- Case {H} : H=100
- Case {M} : M=100
- Case {L} : L=100
- Case {H,M,L} : H=70 M=20 L=10
Further Explanation
- Only Stock with with atleast one
GATE, fully satisfied can get 100 points max- Example:
Q4has 3 sets of 6GATES; Only oneGATEset has to be satsified (have a score present). - The points present must be Multiplied against the particular case it pertains Example:
Q4has case {H,M,L} which means H=70; M=20; L=10 This would results in (70*100%)+(20*50%)+(10*100%)=90 (look back above at the Result table annotations)
2.
- Example:
- Points should still be considered and accounted for even when a gate hasn't been fully satisfied. The gate with MAX points earned should be kept when no gates have been fully satisfied. (Will provide further explanation if not understood)
If we Perform a query to make sense of the tables and data it will look like below
+---------+-----------+---------------+-----------+---------+-----------+---------+
| Origin | Stock | Farm Title | Farm Value| Gate | Size | Score |
+---------+-----------+---------------+-----------+---------+-----------+---------+
| US | P1 | Perdue | 333 | 1 | H | 100 |
| US | P3 | Holstein | 825 | 1 | M | 100 |
| CA | Q4 | FarmOne | 455 | 1 | L | 40 |
| CA | Q4 | FarmOne | 536 | 2 | L | 0 |
| CA | Q4 | FarmOne | 617 | 3 | L | 0 |
| CA | Q4 | FarmOne | 698 | 4 | L | 100 |
| CA | Q4 | FarmOne | 779 | 5 | L | 0 |
| CA | Q4 | FarmOne | 860 | 6 | L | 10 |
| CA | Q4 | Beef Farm | 540 | 1 | H | 0 |
| CA | Q4 | Beef Farm | 550 | 2 | H | 90 |
| CA | Q4 | Beef Farm | 560 | 3 | H | 0 |
| CA | Q4 | Beef Farm | 570 | 4 | H | 100 |
| CA | Q4 | Beef Farm | 580 | 5 | H | 10 |
| CA | Q4 | Beef Farm | 590 | 6 | H | 0 |
| CA | Q4 | CattleOne | 1080 | 1 | M | 0 |
| CA | Q4 | CattleOne | 1100 | 2 | M | 0 |
| CA | Q4 | CattleOne | 1120 | 3 | M | 0 |
| CA | Q4 | CattleOne | 1140 | 4 | M | 50 |
| CA | Q4 | CattleOne | 1160 | 5 | M | 100 |
| CA | Q4 | CattleOne | 1180 | 6 | M | 0 |
| MX | B3 | Cow Mill | 11 | 1 | L | 100 |
| MX | B3 | Dotterers | 98 | 1 | H | 90 |
| MX | B3 | AgriZone | 202 | 1 | M | 100 |
+---------+-----------+---------------+-----------+---------+-----------+---------+
Desire Results
+---------+-------------------+-------+
| Origin | Stock | score |
+---------+-------------------+-------+
| US | P1 | 100 |
| US | P3 | 100 |
| CA | Q4 | 90 |
| MX | B3 | 93 |
+---------+-------------------+-------+
Since origin has a stock which consists of 3 different farms and those farms have 6 gates each. As long as one gate-set (numerically matching gates) is scored to SOME value we can consider the entire STOCK found completely. This is the only way a stock can be considered 100.
Moreover and to reiterate, STOCK Q4 has case: {H,M,L} and all of gate (4) was found to some degree. gate 4 has the score (100% * H) + (50% * M) + (100% * L) which equals (70*100%) + (20*50%) + (10*100%) = 90
Hence: (Taken from above)
| CA | Q4 | 90 |
QED
So what I need help with is creating the subquery/subselect to do make this computation work. I set up everything in the scenario above (along with a query in progress that I've been working with) in the SQL fiddle link below.
Thanks greatly stackoverflow community.
> The above problem in SqlFiddle can be found here <
Upvotes: 8
Views: 647
Answers (2)
Mosty Mostacho
Reputation: 43434
Here is the query I've been working on. However, the results are slighly different from the ones you've posted in your question:
select o.origin_name, s.stock_title, sum(
case f.size
when 'H' then
case
when sizes = 'H,L,M' then 70
when sizes = 'H,M' then 80
when sizes = 'H,L' then 90
when sizes = 'H' then 100
else 0
end
when 'M' then
case
when sizes = 'H,L,M' then 20
when sizes = 'H,M' then 20
when sizes = 'L,M' then 60
when sizes = 'M' then 100
else 0
end
else
case
when sizes = 'H,L,M' then 10
when sizes = 'L,M' then 40
when sizes = 'H,L' then 10
when sizes = 'L' then 100
else 0
end
end * r.score / 100) FinalScore
from farm f
join (
select f.stock_id, group_concat(distinct f.size order by f.size) sizes
from farm f
join results r on f.farm_id = r.farm_id
group by f.stock_id
) stockSizes on f.stock_id = stockSizes.stock_id
join results r on f.farm_id = r.farm_id
join (
select f.stock_id, r.gate_id
from results r
join farm f on r.farm_id = f.farm_id
group by f.stock_id, r.gate_id
having sum(r.score = 0) = 0
) FullGates
on FullGates.stock_id = f.stock_id and FullGates.gate_id = r.gate_id
join stock s on s.stock_id = f.stock_id
join origin o on o.origin_id = s.origin_id
group by o.origin_id, s.stock_id
Result:
+-------------+-------------+------------+ | ORIGIN_NAME | STOCK_TITLE | FINALSCORE | +-------------+-------------+------------+ | US | P1 | 93 | | CA | P3 | 90 | | MX | Q4 | 100 | | MX | B3 | 100 | +-------------+-------------+------------+
Let me know if this did the trick.
Upvotes: 4
Kyra
Reputation: 5407
I would take your original query to get the second last table and change the Select by adding use distinct (found here) and only select Origin, Stock and the calculation for the Score. For example if the score is an average of all of them it would be AVG(Score) where Score would be what you fetched in the original query. If you want to use only a small subset of the items that have the same Origin and Stock to calculate the Score I would use a subquery, with the where matching the Origin and Stick ids, in the select so you have:
Select Origin,
Stock,
(select calculation(Score) from tables where tables.stock_id = .... tables.origin_id = .....)
From....
Hope this helps.
Upvotes: 1
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