CODEWITHSUNDEEP
c#typestypeofgettype
jasonh
jasonh

Reputation: 30303

Type Checking: typeof, GetType, or is?

I've seen many people use the following code:

Type t = typeof(SomeType);
if (t == typeof(int))
    // Some code here

But I know you could also do this:

if (obj1.GetType() == typeof(int))
    // Some code here

Or this:

if (obj1 is int)
    // Some code here

Personally, I feel the last one is the cleanest, but is there something I'm missing? Which one is the best to use, or is it personal preference?

Upvotes: 1932

Views: 1577287

Answers (16)

AllenG
AllenG

Reputation: 8190

It depends on what I'm doing. If I need a bool value (say, to determine if I'll cast to an int), I'll use is. If I actually need the type for some reason (say, to pass to some other method) I'll use GetType().

Upvotes: 4

StriplingWarrior
StriplingWarrior

Reputation: 156654

I believe the last one also looks at inheritance (e.g. Dog is Animal == true), which is better in most cases.

Upvotes: 6

AnthonyVO
AnthonyVO

Reputation: 3983

If you are only interested in the base types in an object and you need to handle it differently based on its type then you could do the following.

TypeCode typeCode = Type.GetTypeCode(value.GetType());

switch (typeCode)
{
    case TypeCode.Empty:
    case TypeCode.DBNull:
        return "";

    case TypeCode.Boolean:
    case TypeCode.Object:
    case TypeCode.DateTime:
    case TypeCode.SByte:
    case TypeCode.Byte:
    case TypeCode.Int16:
    case TypeCode.UInt16:
    case TypeCode.Int32:
    case TypeCode.UInt32:
    case TypeCode.Int64:
    case TypeCode.UInt64:
    case TypeCode.Single:
    case TypeCode.Double:
    case TypeCode.Decimal:
        return "do something";
        
    case TypeCode.Char:
    case TypeCode.String:
    default:
        return value.ToString();
}

Upvotes: -1

asciidude
asciidude

Reputation: 459

I found checking if the type of something is equal to something is done by the following:

variableName.GetType() == typeof(int)

Upvotes: 1

Scott Langham
Scott Langham

Reputation: 60411

1.

Type t = typeof(obj1);
if (t == typeof(int))

This is illegal, because typeof only works on types, not on variables. I assume obj1 is a variable. So, in this way typeof is static, and does its work at compile time instead of runtime.

2.

if (obj1.GetType() == typeof(int))

This is true if obj1 is exactly of type int. If obj1 derives from int, the if condition will be false.

3.

if (obj1 is int)

This is true if obj1 is an int, or if it derives from a class called int, or if it implements an interface called int.

Upvotes: 115

Andrew Hare
Andrew Hare

Reputation: 351616

Use typeof when you want to get the type at compilation time. Use GetType when you want to get the type at execution time. There are rarely any cases to use is as it does a cast and, in most cases, you end up casting the variable anyway.

There is a fourth option that you haven't considered (especially if you are going to cast an object to the type you find as well); that is to use as.

Foo foo = obj as Foo;

if (foo != null)
    // your code here

This only uses one cast whereas this approach:

if (obj is Foo)
    Foo foo = (Foo)obj;

requires two.

Update (Jan 2020):

  • As of C# 7+, you can now cast inline, so the 'is' approach can now be done in one cast as well.

Example:

if(obj is Foo newLocalFoo)
{
    // For example, you can now reference 'newLocalFoo' in this local scope
    Console.WriteLine(newLocalFoo);
}

Upvotes: 255

Jimmy
Jimmy

Reputation: 91502

All are different.

  • typeof takes a type name (which you specify at compile time).
  • GetType gets the runtime type of an instance.
  • is returns true if an instance is in the inheritance tree.

Example

class Animal { } 
class Dog : Animal { }

void PrintTypes(Animal a) { 
    Console.WriteLine(a.GetType() == typeof(Animal)); // false 
    Console.WriteLine(a is Animal);                   // true 
    Console.WriteLine(a.GetType() == typeof(Dog));    // true
    Console.WriteLine(a is Dog);                      // true 
}

Dog spot = new Dog(); 
PrintTypes(spot);

What about typeof(T)? Is it also resolved at compile time?

Yes. T is always what the type of the expression is. Remember, a generic method is basically a whole bunch of methods with the appropriate type. Example:

string Foo<T>(T parameter) { return typeof(T).Name; }

Animal probably_a_dog = new Dog();
Dog    definitely_a_dog = new Dog();

Foo(probably_a_dog); // this calls Foo<Animal> and returns "Animal"
Foo<Animal>(probably_a_dog); // this is exactly the same as above
Foo<Dog>(probably_a_dog); // !!! This will not compile. The parameter expects a Dog, you cannot pass in an Animal.

Foo(definitely_a_dog); // this calls Foo<Dog> and returns "Dog"
Foo<Dog>(definitely_a_dog); // this is exactly the same as above.
Foo<Animal>(definitely_a_dog); // this calls Foo<Animal> and returns "Animal". 
Foo((Animal)definitely_a_dog); // this does the same as above, returns "Animal"

Upvotes: 2293

JoelC
JoelC

Reputation: 3754

If you're using C# 7, then it is time for an update to Andrew Hare's great answer. Pattern matching has introduced a nice shortcut that gives us a typed variable within the context of the if statement, without requiring a separate declaration/cast and check:

if (obj1 is int integerValue)
{
    integerValue++;
}

This looks pretty underwhelming for a single cast like this, but really shines when you have many possible types coming into your routine. The below is the old way to avoid casting twice:

Button button = obj1 as Button;
if (button != null)
{
    // do stuff...
    return;
}
TextBox text = obj1 as TextBox;
if (text != null)
{
    // do stuff...
    return;
}
Label label = obj1 as Label;
if (label != null)
{
    // do stuff...
    return;
}
// ... and so on

Working around shrinking this code as much as possible, as well as avoiding duplicate casts of the same object has always bothered me. The above is nicely compressed with pattern matching to the following:

switch (obj1)
{
    case Button button:
        // do stuff...
        break;
    case TextBox text:
        // do stuff...
        break;
    case Label label:
        // do stuff...
        break;
    // and so on...
}

EDIT: Updated the longer new method to use a switch as per Palec's comment.

Upvotes: 24

P Daddy
P Daddy

Reputation: 29537

Type t = typeof(obj1);
if (t == typeof(int))
    // Some code here

This is an error. The typeof operator in C# can only take type names, not objects.

if (obj1.GetType() == typeof(int))
    // Some code here

This will work, but maybe not as you would expect. For value types, as you've shown here, it's acceptable, but for reference types, it would only return true if the type was the exact same type, not something else in the inheritance hierarchy. For instance:

class Animal{}
class Dog : Animal{}

static void Foo(){
    object o = new Dog();

    if(o.GetType() == typeof(Animal))
        Console.WriteLine("o is an animal");
    Console.WriteLine("o is something else");
}

This would print "o is something else", because the type of o is Dog, not Animal. You can make this work, however, if you use the IsAssignableFrom method of the Type class.

if(typeof(Animal).IsAssignableFrom(o.GetType())) // note use of tested type
    Console.WriteLine("o is an animal");

This technique still leaves a major problem, though. If your variable is null, the call to GetType() will throw a NullReferenceException. So to make it work correctly, you'd do:

if(o != null && typeof(Animal).IsAssignableFrom(o.GetType()))
    Console.WriteLine("o is an animal");

With this, you have equivalent behavior of the is keyword. Hence, if this is the behavior you want, you should use the is keyword, which is more readable and more efficient.

if(o is Animal)
    Console.WriteLine("o is an animal");

In most cases, though, the is keyword still isn't what you really want, because it's usually not enough just to know that an object is of a certain type. Usually, you want to actually use that object as an instance of that type, which requires casting it too. And so you may find yourself writing code like this:

if(o is Animal)
    ((Animal)o).Speak();

But that makes the CLR check the object's type up to two times. It will check it once to satisfy the is operator, and if o is indeed an Animal, we make it check again to validate the cast.

It's more efficient to do this instead:

Animal a = o as Animal;
if(a != null)
    a.Speak();

The as operator is a cast that won't throw an exception if it fails, instead returning null. This way, the CLR checks the object's type just once, and after that, we just need to do a null check, which is more efficient.

But beware: many people fall into a trap with as. Because it doesn't throw exceptions, some people think of it as a "safe" cast, and they use it exclusively, shunning regular casts. This leads to errors like this:

(o as Animal).Speak();

In this case, the developer is clearly assuming that o will always be an Animal, and as long as their assumption is correct, everything works fine. But if they're wrong, then what they end up with here is a NullReferenceException. With a regular cast, they would have gotten an InvalidCastException instead, which would have more correctly identified the problem.

Sometimes, this bug can be hard to find:

class Foo{
    readonly Animal animal;

    public Foo(object o){
        animal = o as Animal;
    }

    public void Interact(){
        animal.Speak();
    }
}

This is another case where the developer is clearly expecting o to be an Animal every time, but this isn't obvious in the constructor, where the as cast is used. It's not obvious until you get to the Interact method, where the animal field is expected to be positively assigned. In this case, not only do you end up with a misleading exception, but it isn't thrown until potentially much later than when the actual error occurred.

In summary:

  • If you only need to know whether or not an object is of some type, use is.

  • If you need to treat an object as an instance of a certain type, but you don't know for sure that the object will be of that type, use as and check for null.

  • If you need to treat an object as an instance of a certain type, and the object is supposed to be of that type, use a regular cast.

Upvotes: 64

Paulos02
Paulos02

Reputation: 181

if (c is UserControl) c.Enabled = enable;

Upvotes: -4

Yahoo Serious
Yahoo Serious

Reputation: 3928

I had a Type-property to compare to and could not use is (like my_type is _BaseTypetoLookFor), but I could use these:

base_type.IsInstanceOfType(derived_object);
base_type.IsAssignableFrom(derived_type);
derived_type.IsSubClassOf(base_type);

Notice that IsInstanceOfType and IsAssignableFrom return true when comparing the same types, where IsSubClassOf will return false. And IsSubclassOf does not work on interfaces, where the other two do. (See also this question and answer.)

public class Animal {}
public interface ITrainable {}
public class Dog : Animal, ITrainable{}

Animal dog = new Dog();

typeof(Animal).IsInstanceOfType(dog);     // true
typeof(Dog).IsInstanceOfType(dog);        // true
typeof(ITrainable).IsInstanceOfType(dog); // true

typeof(Animal).IsAssignableFrom(dog.GetType());      // true
typeof(Dog).IsAssignableFrom(dog.GetType());         // true
typeof(ITrainable).IsAssignableFrom(dog.GetType()); // true

dog.GetType().IsSubclassOf(typeof(Animal));            // true
dog.GetType().IsSubclassOf(typeof(Dog));               // false
dog.GetType().IsSubclassOf(typeof(ITrainable)); // false

Upvotes: 17

Muhammad Awais
Muhammad Awais

Reputation: 4502

Used to obtain the System.Type object for a type. A typeof expression takes the following form:

System.Type type = typeof(int);

Example:

    public class ExampleClass
    {
       public int sampleMember;
       public void SampleMethod() {}

       static void Main()
       {
          Type t = typeof(ExampleClass);
          // Alternatively, you could use
          // ExampleClass obj = new ExampleClass();
          // Type t = obj.GetType();

          Console.WriteLine("Methods:");
          System.Reflection.MethodInfo[] methodInfo = t.GetMethods();

          foreach (System.Reflection.MethodInfo mInfo in methodInfo)
             Console.WriteLine(mInfo.ToString());

          Console.WriteLine("Members:");
          System.Reflection.MemberInfo[] memberInfo = t.GetMembers();

          foreach (System.Reflection.MemberInfo mInfo in memberInfo)
             Console.WriteLine(mInfo.ToString());
       }
    }
    /*
     Output:
        Methods:
        Void SampleMethod()
        System.String ToString()
        Boolean Equals(System.Object)
        Int32 GetHashCode()
        System.Type GetType()
        Members:
        Void SampleMethod()
        System.String ToString()
        Boolean Equals(System.Object)
        Int32 GetHashCode()
        System.Type GetType()
        Void .ctor()
        Int32 sampleMember
    */

This sample uses the GetType method to determine the type that is used to contain the result of a numeric calculation. This depends on the storage requirements of the resulting number.

    class GetTypeTest
    {
        static void Main()
        {
            int radius = 3;
            Console.WriteLine("Area = {0}", radius * radius * Math.PI);
            Console.WriteLine("The type is {0}",
                              (radius * radius * Math.PI).GetType()
            );
        }
    }
    /*
    Output:
    Area = 28.2743338823081
    The type is System.Double
    */

Upvotes: 0

Alexander Vasilyev
Alexander Vasilyev

Reputation: 1313

Performance test typeof() vs GetType():

using System;
namespace ConsoleApplication1
    {
    class Program
    {
        enum TestEnum { E1, E2, E3 }
        static void Main(string[] args)
        {
            {
                var start = DateTime.UtcNow;
                for (var i = 0; i < 1000000000; i++)
                    Test1(TestEnum.E2);
                Console.WriteLine(DateTime.UtcNow - start);
            }
            {
                var start = DateTime.UtcNow;
                for (var i = 0; i < 1000000000; i++)
                    Test2(TestEnum.E2);
                Console.WriteLine(DateTime.UtcNow - start);
            }
            Console.ReadLine();
        }
        static Type Test1<T>(T value) => typeof(T);
        static Type Test2(object value) => value.GetType();
    }
}

Results in debug mode:

00:00:08.4096636
00:00:10.8570657

Results in release mode:

00:00:02.3799048
00:00:07.1797128

Upvotes: -5

androidrill
androidrill

Reputation: 99

You can use "typeof()" operator in C# but you need to call the namespace using System.IO; You must use "is" keyword if you wish to check for a type.

Upvotes: -5

bobobobo
bobobobo

Reputation: 67286

I prefer is

That said, if you're using is, you're likely not using inheritance properly.

Assume that Person : Entity, and that Animal : Entity. Feed is a virtual method in Entity (to make Neil happy)

class Person
{
  // A Person should be able to Feed
  // another Entity, but they way he feeds
  // each is different
  public override void Feed( Entity e )
  {
    if( e is Person )
    {
      // feed me
    }
    else if( e is Animal )
    {
      // ruff
    }
  }
}

Rather

class Person
{
  public override void Feed( Person p )
  {
    // feed the person
  }
  public override void Feed( Animal a )
  {
    // feed the animal
  }
}

Upvotes: 12

thecoop
thecoop

Reputation: 46138

The last one is cleaner, more obvious, and also checks for subtypes. The others do not check for polymorphism.

Upvotes: 0

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