CODEWITHSUNDEEP
phpurlparametersget
Danny
Danny

Reputation: 334

Pass multiple variables via URL and reading all of them on next page

I have a link that points to a webpage e.g. "land.php". The link looks like this:

<a href="land.php?id=1&cd=a">link</a>

this takes me to the page land.php where I can read the first parametere with $id (and it is equal to 1, correctly), but I cannot read the second one. I either tried with $cd or $_GET['cd']. None of them works.

if I tried isset($cd) it says false. Same thing for isset($_GET['cd']).

How can I pass the second parameter too (and read it!)?

EDIT:

some code (so people are happy. I think it's pointless in this case..).

land.php

<?php
if($_GET['cd']==a)
    echo "<h2>HI</h2>";
else
    echo "<h2>BY</h2>";
?>

if I use $cd instead of $_GET['cd'] it doesn't work anyway..

EDIT2 I don't get any syntax error, it just doesn't behave how expected.

Upvotes: 3

Views: 24598

Answers (3)

Phil
Phil

Reputation: 164731

$_GET['cd'] is the correct syntax. Are you actually on the land.php page, ie does your browser's address bar read something like

example.com/land.php?id=1&cd=a

Also, it looks like you have register_globals enabled if you can read $id. This is a very bad idea.

Update

Your code snippet contains syntax errors. I recommend the following, including enabling decent error reporting for development

ini_set('display_errors', 'On');
error_reporting(E_ALL);

if(isset($_GET['cd']) && $_GET['cd'] == 'a') {
    echo "<h2>HI</h2>";
} else {
    echo "<h2>BY</h2>";
}

Upvotes: 0

Ragnar123
Ragnar123

Reputation: 5204

The value is stored in $_GET['cd'].

Try printing out the $_GET array, with print_r($_GET);

print_r($_GET) should output 

Array
(
    [id] => 1
    [cd] => a
)

This should ofcourse be in the land.php page, as the get variables are only available in the requested page.

Upvotes: 1

Andreas Hagen
Andreas Hagen

Reputation: 2325

Your server might be set up to accept semicolon instead of ampersands. Try replacing & with ;

Upvotes: 0

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