andrew slaughter
andrew slaughter

Reputation: 1127

Return value in SQL Server stored procedure

I have a stored procedure that has an if statement in it. If the number of rows counted is greater than 0 then it should set the only output parameter @UserId to 0

However it only returns a value in the second part of the query.

@EmailAddress varchar(200),
@NickName varchar(100),
@Password varchar(150),
@Sex varchar(50),
@Age int,
@EmailUpdates int,
@UserId int OUTPUT
IF 
    (SELECT COUNT(UserId) FROM RegUsers WHERE EmailAddress = @EmailAddress) > 0
    BEGIN
        SET @UserId = 0
    END
ELSE
    BEGIN
        INSERT INTO RegUsers (EmailAddress,NickName,PassWord,Sex,Age,EmailUpdates) VALUES (@EmailAddress,@NickName,@Password,@Sex,@Age,@EmailUpdates)
        SELECT SCOPE_IDENTITY()
    END

END

Upvotes: 15

Views: 146344

Answers (4)

Arbejdsglæde
Arbejdsglæde

Reputation: 14098

I can recommend make pre-init of future index value, this is very usefull in a lot of case like multi work, some export e.t.c.

just create additional User_Seq table: with two fields: id Uniq index and SeqVal nvarchar(1)

and create next SP, and generated ID value from this SP and put to new User row!

CREATE procedure [dbo].[User_NextValue]
as
begin
    set NOCOUNT ON


    declare @existingId int = (select isnull(max(UserId)+1, 0)  from dbo.User)

    insert into User_Seq (SeqVal) values ('a')
    declare @NewSeqValue int = scope_identity()     

    if @existingId > @NewSeqValue 
    begin  

        set identity_insert User_Seq  on
        insert into User_Seq (SeqID) values (@existingId)     
        set @NewSeqValue = scope_identity()     
    end

    delete from User_Seq WITH (READPAST)

return @NewSeqValue

end

Upvotes: 4

KEERTHANA
KEERTHANA

Reputation: 1

@EmailAddress varchar(200),
@NickName varchar(100),
@Password varchar(150),
@Sex varchar(50),
@Age int,
@EmailUpdates int,
@UserId int OUTPUT
DECLARE @AA INT
SET @AA=(SELECT COUNT(UserId) FROM RegUsers WHERE EmailAddress = @EmailAddress)

IF @AA> 0
    BEGIN
        SET @UserId = 0
    END
ELSE
    BEGIN
        INSERT INTO RegUsers (EmailAddress,NickName,PassWord,Sex,Age,EmailUpdates) VALUES (@EmailAddress,@NickName,@Password,@Sex,@Age,@EmailUpdates)
        SELECT SCOPE_IDENTITY()
    END

END

Upvotes: 0

Curtis
Curtis

Reputation: 103428

You can either do 1 of the following:

Change:

SET @UserId = 0 to SELECT @UserId

This will return the value in the same way your 2nd part of the IF statement is.


Or, seeing as @UserId is set as an Output, change:

SELECT SCOPE_IDENTITY() to SET @UserId = SCOPE_IDENTITY()


It depends on how you want to access the data afterwards. If you want the value to be in your result set, use SELECT. If you want to access the new value of the @UserId parameter afterwards, then use SET @UserId


Seeing as you're accepting the 2nd condition as correct, the query you could write (without having to change anything outside of this query) is:

@EmailAddress varchar(200),
@NickName varchar(100),
@Password varchar(150),
@Sex varchar(50),
@Age int,
@EmailUpdates int,
@UserId int OUTPUT
IF 
    (SELECT COUNT(UserId) FROM RegUsers WHERE EmailAddress = @EmailAddress) > 0
    BEGIN
        SELECT 0
    END
ELSE
    BEGIN
        INSERT INTO RegUsers (EmailAddress,NickName,PassWord,Sex,Age,EmailUpdates) VALUES (@EmailAddress,@NickName,@Password,@Sex,@Age,@EmailUpdates)
        SELECT SCOPE_IDENTITY()
    END

END

Upvotes: 9

Andrey Gurinov
Andrey Gurinov

Reputation: 2895

Try to call your proc in this way:

DECLARE @UserIDout int

EXEC YOURPROC @EmailAddress = 'sdfds', @NickName = 'sdfdsfs', ..., @UserId = @UserIDout OUTPUT

SELECT @UserIDout 

Upvotes: 2

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