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Chris Marshall
Chris Marshall

Reputation: 5332

UIStoryboard: What's the Correct Way to Get the Active Storyboard?

I am currently furiously digging through all the docs, and haven't quite found what I'm looking for. I suspect it is a real d'oh! answer.

I simply need to find the active storyboard in the main bundle, and want to know the best way to do this.

This is so that I can use the [UIStoryboard storyboardWithName:@"XXX" bundle:mainBundle] to extract the running storyboard.

I know how to kludge it by switching on the idiom, but I feel that this is a...kludge.

What's a correct way of doing this?

Upvotes: 50

Views: 38979

Answers (5)

Ashish P
Ashish P

Reputation: 1473

The better approach would be to get existing storyboard instance from window's rootViewController if not available then create a new instance.

let storyboard = self.window?.rootViewController?.storyboard ?? UIStoryboard.init(name: "Main", bundle: nil)

Also using globally accessible helper functions like these can be a good idea provided that you pass the already active storyboard as parameter.

class Helper {
    static func getLoginVC(storyboard: UIStoryboard) -> LoginVC {
         return storyboard.instantiateViewController(withIdentifier: String(describing: LoginVC.self)) as! LoginVC
    }
}

you can pass the active storyboard instance from a controller like this -

let loginVC = Helper.getLoginVC(storyboard: self.storyboard)

In case you are trying to access storyboard from appDelegate or sceneDelegate you can use -

let storyboard = self.window?.rootViewController?.storyboard ?? UIStoryboard.init(name: "Main", bundle: nil)
let loginVC = Helper.getLoginVC(storyboard: storyboard)

let navigationController = UINavigationController.init(rootViewController: loginVC)
self.window?.rootViewController = navigationController
self.window?.makeKeyAndVisible()

Upvotes: 1

olivaresF
olivaresF

Reputation: 1379

In case you want to get the active storyboard for a viewController, there's a storyboard property. This is how I solved it, instead of making a new instance:

LoginViewController *vc = [navController.storyboard instantiateViewControllerWithIdentifier:@"firstLaunch"];
[navController presentModalViewController:vc animated:YES];

In Swift you'd call:

let loginViewController = navigationController?.storyboard?.instantiateViewController(withIdentifier: "firstLaunch") as! LoginViewController
navigationController?.present(loginViewController, animated: true, completion: nil)

You could also be a lot safer by using guards against the navigation controller and the storyboard. I've used as! so as to guarantee that you're getting a LoginController.

Upvotes: 41

nburk
nburk

Reputation: 22751

In Swift, you'd use the following syntax:

let storyboard = UIStoryboard(name: "Main", bundle: nil)

Note that passing nil to bundle will make the call refer to your main bundle automatically.

If you're in a view controller that you have on the Storyboard and want to instantiate the Storyboard from there directly, you can just do:

let storyboard: UIStoryboard? = self.storyboard // call this inside a VC that is on the Storyboard

Note that in the last case, self.storyboard will return an optional Storyboard (Storyboard?), so if you'd like to use it unwrap it like so:

if let storyboard = self.storyboard {
  // access storyboard here
}

Upvotes: 7

Imran Khan
Imran Khan

Reputation: 317

I have just copy pasted the code form above updated question so that everyone can see it as an answer.

UIStoryboard *st = [UIStoryboard storyboardWithName:[[NSBundle mainBundle].infoDictionary objectForKey:@"UIMainStoryboardFile"] bundle:[NSBundle mainBundle]];

Upvotes: 0

Chris Marshall
Chris Marshall

Reputation: 5332

OK. As my comment above indicates, I found the answer to the (badly phrased question):

I wanted to be able to get the main (not active) storyboard, as I'm not using multiple storyboards per incarnation. I'm using the standard model of 1 storyboard for iPhone, and 1 for iPad. I just wanted the cleanest way to get the storyboard, so that I could use it to generate a view controller.

I found the answer in this post on Stack Overflow, and implemented it with the following code:

UIStoryboard *st = [UIStoryboard storyboardWithName:[[NSBundle mainBundle].infoDictionary objectForKey:@"UIMainStoryboardFile"] bundle:[NSBundle mainBundle]];

Upvotes: 27

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