CODEWITHSUNDEEP
php
vvr
vvr

Reputation: 466

How to ignore if array(0) is null php

How to ignore if array(0) is null php

When i am print the value the array is like this: Array ( [0] => )

if i print count($testArray) it is showing 1

But if the array value is comes like this i don't want to insert it into the database. Please suggest how can i do this.

Update:

var_dump result: array(1) { [0]=> string(0) "" }

Upvotes: 1

Views: 3723

Answers (5)

DagicCross
DagicCross

Reputation: 401

I was trying to ignore an empty value but some of the codes didn't work. So I tried this and works, maybe this code will help someone out there.

if (empty($YourValue)){ continue; } else { echo $YourValue; }

The code continue skips your empty value.

It helps me creating a navbar inside <li> ... </li> code for some reason.

Upvotes: 0

Patroklo
Patroklo

Reputation: 516

You can try

if(!isset($testArray[0]))
{
    //here the zero key has null value
}

or 

if($testArray[0] == NULL)
{
    //here the zero key has null value
}

But try first:

var_dump($testArray);

And let us know what it's shown.

Upvotes: 0

Baba
Baba

Reputation: 95151

This would help you filter the array 

    $array1 = array("a"=>1, "b"=>2, "c"=>3, "d"=>4, "e"=>5,"f"=>"","i"=>0);
    function filter($var)
    {
        return !empty($var);
    }
    var_dump(array_filter($array1, "filter"));

Output

    array
      'a' => int 1
      'b' => int 2
      'c' => int 3
      'd' => int 4
      'e' => int 5

Upvotes: 0

vicky
vicky

Reputation: 705

Use this

 array_filter($testArray);

Upvotes: 8

Travesty3
Travesty3

Reputation: 14479

if (!empty($testArray[0]))
    // do something

OR

foreach ($testArray as $value)
{
    if (!empty($value))
    {
        // do something
    }
}

Upvotes: 0

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