Patrick
Patrick

Reputation: 4905

php class function wrapper

this is my class:

class toyota extends car {
    function drive() {
    }
    function break() {
    }
}

class car {
    function pre() {
    }
}

Is there any way I can do so that when I run $car->drive(), $car->break() (or any other function in toyota), it would call $car->pre() first before calling the functions in toyota?

Upvotes: 6

Views: 6635

Answers (5)

Gabriel Chung
Gabriel Chung

Reputation: 1587

If you are using PHP5 (>=5.3.2), there is a solution that works with declaring all methods as private. This will enforce method call from single function call:

exec_method()

To run at: http://ideone.com/cvfCXm

The code snippet is here:

<?php

    class car {

        //method to get class method
        public function get_method($method_name) {
            $class = new ReflectionClass(get_class($this));
            $method = $class->getMethod($method_name);
            $method->setAccessible(true);
            return $method;
        }

        public function exec_method($method_name, $arg_args=array()) {

            //execute the pre() function before the specified method
            $this->pre();

            //execute the specified method
            $this->get_method($method_name)->invokeArgs($this, $arg_args);
        }

        public function pre() {
            echo 'pre';
            echo '<br />';
        }
    }

    class toyota extends car {
        private function drive() {
            echo 'drive';
            echo '<br />';
        }

        private function brake() {
            echo 'brake';
            echo '<br />';
        }
    }

    $toyota = new toyota();
    $toyota->exec_method('drive');
    $toyota->exec_method('brake');
?>

Reference:

Answer to Best practices to test protected methods with PHPUnit [closed]

Upvotes: 0

Starx
Starx

Reputation: 79031

This will better done with the magic methods called __call()

public function __call($name, $arguments)
{
    $this -> pre();
    return $this -> $name($arguments);
}

What is this method? It overrides the default method call, so that preCall State can be invoked.

Your toyota class

class toyota extends car {    

    public function __call($name, $arguments)
    {
        $this -> pre();
        return call_user_func_array(array($this, $name), $arguments);
    }

    function drive() {
    }
    function break() {
    }
}

Upvotes: 0

Bjoern
Bjoern

Reputation: 16304

Just add a constructor, like this...

class toyota extends car {
    function __construct() { 
        $this->pre();
    }   

    function drive() {
        echo "drive!";
    }

    function dobreak() {
        echo "break!";
    }
}

class car {
    function pre() {
        echo "Hello!";
    }
}

$car = new toyota();
$car->drive();
$car->dobreak();

Classes which have a constructor method call this method on each newly-created object, so it is suitable for any initialization that the object may need before it is used.

break is reserved, so you shouldn't use this as a function name.

Upvotes: -2

zerkms
zerkms

Reputation: 255045

Yep. You could use protected and some __call magic:

class toyota extends car {
    protected function drive() {
        echo "drive\n";
    }
    protected function dobreak() {
        echo "break\n";
    }
}

class car {
    public function __call($name, $args)
    {
        if (method_exists($this, $name)) {
            $this->pre();
            return call_user_func_array(array($this, $name), $args);
        }


    }

    function pre() {
        echo "pre\n";
    }
}

$car = new toyota();
$car->drive();
$car->dobreak();

http://ideone.com/SGi1g

Upvotes: 14

Gohn67
Gohn67

Reputation: 10648

You could do the following, but I don't think that is what you want.

class toyota extends car {
    function drive() {
         $this->pre();
    }
    function break() {
         $this->pre();
    }
}

class car {
    function pre() {
    }
}

You may want to look into PHP specific magic methods. http://php.net/manual/en/language.oop5.magic.php

Upvotes: 1

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