Reputation: 14671
I have a table like:
ID | LABEL | SOME_VALUE
1 a rand_1
2 a NULL
3 b rand_9
4 c rand_3
5 c rand_3
6 c rand_3
7 d NULL
8 d rand_4
As you can see, ID is unique, label is not unique (can be 1 or more) and some_value is also not unique.
What I want to do is the following:
I want to get a unique list of LABELS, which exist in the database in more than one rows (min 2) and of which rows has SOME_VALUE not NULL.
So I would get:
ID | LABEL | SOME_VALUE
1 a rand_1
2 a NULL
7 d NULL
8 d rand_4
in return.
How can I achieve this?
Upvotes: 0
Views: 117
Reputation: 12973
This should work -
SELECT test.*
FROM (
SELECT label
FROM test
GROUP BY Label
HAVING COUNT(DISTINCT IFNULL(some_value, '~null~')) > 1
) AS tmp
INNER JOIN test
ON tmp.label = test.label;
Upvotes: 1
Reputation: 19356
There are two versions. First one does exactly as listed in results, eliminating rand_3 because even though it appears three times all the values are the same (I don't see distinct condition specified in question).
There must be a better way, but as they say I can't brain today, I have the dumb :-)
select *
from tbl
inner join
(
select label
FROM tbl
GROUP BY Label
HAVING count (distinct some_value)
+ sum(distinct case when some_value is null then 1 else 0 end) > 1
) a
on tbl.label = a.label
Second one retrieves C also following the requirements (some_value being not null for at least one of some_value).
select *
from tbl
inner join
(
select label
FROM tbl
GROUP BY Label
HAVING count(*) > 1 and count(some_value) > 0
) a
on tbl.label = a.label
Upvotes: 2
Reputation: 39773
SELECT t1.*
FROM yourTable t1
JOIN yourTable t2
ON t1.LABEL = t2.LABEL
AND t1.ID < t2.ID
WHERE t1.SOME_VALUE IS NOT NULL
OR t2.SOME_VALUE IS NOT NULL
Upvotes: 1
Reputation: 21034
The HAVING parameter limits grouped items:
SELECT
Label
FROM dbo.TableName
WHERE NOT Some_Value IS NULL
GROUP BY Label
HAVING COUNT(*) > 2
Upvotes: 2