CODEWITHSUNDEEP
pythonweb-scrapinglxmlpython-2.7
Zain Khan
Zain Khan

Reputation: 3793

Fetching data using Python & lxml

I have a my HTML which looks like below. I would like to get the text which is in the <span class="zzAggregateRatingStat">. According to the e.g given below I would get 3 and 5.

For this work I am using Python2.7 & lxml

<div class="pp-meta-review">
<span class="zrvwidget" style="">
    <span g:inline="true" g:type="NumUsersFoundThisHelpful" g:hideonnoratings="true" g:entity.annotation.groups="maps"    g:entity.annotation.id="http://maps.google.com/?q=Central+Kia+of+Irving++(972)+659-2204+loc:+1600+East+Airport+Freeway,+Irving,+TX+75062&gl=US&sll=32.83624,-96.92526" g:entity.annotation.author="AIe9_BH8MR-1JD_4BhwsKrGCazUyU5siqCtjchckDcg5BAl5rOLd9nvhJJDTrtjL-xFI8D42bD_7">
        <span class="zzNumUsersFoundThisHelpfulActive" zzlabel="helpful">
            <span>
                <span class="zzAggregateRatingStat">3</span>
            </span>
            <span>
                <span>&nbsp;</span>
                      out of
                <span>&nbsp;</span>
            </span>
            <span>
                <span class="zzAggregateRatingStat">5</span>
            </span>
            <span>
                <span>&nbsp;</span>
                    people found this review helpful.
            </span>
       </span>
   </span>
</span>
</div>

Upvotes: 0

Views: 2217

Answers (2)

sente
sente

Reputation: 2367

The following code works with your input:

import lxml.html
root = lxml.html.parse('text.html').getroot()
for span in root.xpath('//span[@class="zzAggregateRatingStat"]'):
    print span.text

it prints:

3
5

I prefer using lxml's xpath over CSSSelectors though they can both do the job.

ChrisP's example prints 3 but if you run it on your actual input we get errors:

$ python chrisp.py
Traceback (most recent call last):
  File "chrisp.py", line 6, in <module>
    doc = fromstring(text)
  File "lxml.etree.pyx", line 2532, in lxml.etree.fromstring (src/lxml/lxml.etree.c:48270)
  File "parser.pxi", line 1545, in lxml.etree._parseMemoryDocument (src/lxml/lxml.etree.c:71812)
  File "parser.pxi", line 1424, in lxml.etree._parseDoc (src/lxml/lxml.etree.c:70673)
  File "parser.pxi", line 938, in lxml.etree._BaseParser._parseDoc (src/lxml/lxml.etree.c:67442)
  File "parser.pxi", line 539, in lxml.etree._ParserContext._handleParseResultDoc (src/lxml/lxml.etree.c:63824)
  File "parser.pxi", line 625, in lxml.etree._handleParseResult (src/lxml/lxml.etree.c:64745)
  File "parser.pxi", line 565, in lxml.etree._raiseParseError (src/lxml/lxml.etree.c:64088)
lxml.etree.XMLSyntaxError: EntityRef: expecting ';', line 3, column 210

ChrisP's code can be changed to use lxml.html.fromstring - which is a more lenient parser - instead of lxml.etree.fromstring.

If this change is made it prints 3.

Upvotes: 4

ChrisP
ChrisP

Reputation: 5942

This is clearly documented at the lxml website

from lxml.etree import fromstring
from lxml.cssselect import CSSSelector

sel = CSSSelector('.zzAggregateRatingStat')
text = '<span><span class="zzAggregateRatingStat">3</span></span>'
doc = fromstring(text)
el = sel(doc)[0]
print el.text

Upvotes: 0

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