Reputation: 4257
I have read the answer for difference between deep copy and shallow copy from the post, What is the difference between a deep copy and a shallow copy? . Now I got some doubt that when we made a shallow copy by
newArray = [NSmutableArray arrayWithArray:oldArray];
the new array will point to oldArray. (As from the figure). Now what happen when I remove object from newArray? As from figure, it should remove same element from oldArray too !!! It seems like
newArray = oldArray
is a shallow copy and newArray = [NSmutableArray arrayWithArray:oldArray];
is deep copy. Is it right?
Upvotes: 16
Views: 19141
Reputation: 16725
newArary = oldArray
isn't a copy at all. You end up with two pointers pointing to the exact same memory location.
newArray = [NSMutableArray arrayWithArray:oldArray];
is a shallow copy. You end up with two distinct arrays, so if you were to remove or add items from one array, it wouldn't affect the other array. However, the items in the two arrays are identical. If the first element of oldArray
were an NSMutableDictionary
and you added a key to it, you'd see that change on the first element of newArray
as well (since those two objects are the same).
To do a deep copy, you would have to make a new array, and each element of the new array would be a deep copy of the corresponding element of the old array. (Yes, that definition is recursive).
Upvotes: 43
Reputation: 3195
You can also call [[NSArray alloc] initWithArray:arraytoBeCopied copyItems:YES];
Upvotes: 2
Reputation: 49
In Objective-C "Copy" keyword just increase the "Retain Count" of the object. So only use of "Copy" will not perform a copy.
But when we make a change in object, then Objective-C create a copy of the original object at that time.
Please correct me if i am wrong.
Thanks
Upvotes: -8
Reputation: 55563
First of all, NSArray
's don't have a deep copy function. However, you can make a deep copy function by doing the following:
@interface NSArray(deepCopy)
-(NSArray *) deepCopy;
@end
@implementation
-(NSArray *) deepCopy
{
NSMutableArray *ret = [NSMutableArray array];
for (id val in self)
{
if ([val conformsToProtocol:@protocol(NSCopying)])
{
[ret addObject:[val copy]];
}
else
{
[ret addObject:val];
}
}
return ret;
}
@end
Second of all, newArray = oldArray
does not copy the array. It simply makes newArray
point to the array that oldArray
points to.
Third, +arrayWithArray:
does a shallow copy of the array, meaning the individual objects are NOT copied.
Upvotes: 11