python list iteration

Question

I have a list iteration in python defined like this:

for i in range(5):
    for j in range(5):
        if i != j:
            print i , j

So for each element in my defined range [0..5] I want to get each element i, but also all other elements which are not i.

This code does exactly as I expect, but is there a cleaner way of doing this?

Answer 1

[(x,y)for x in range(5) for y in range(5) if x!=y]

Answer 2

Use itertools.permutations:

import itertools as it
for i, j in it.permutations(range(5), 2):
    print i, j