CODEWITHSUNDEEP
c#regex
user1260827
user1260827

Reputation: 1520

regexp for find number in a string

I have the following string fromat:

session=11;reserID=1000001

How to get string array of number?

My code:

 var value = "session=11;reserID=1000001";
 var numbers =  Regex.Split(value, @"^\d+");

Upvotes: 0

Views: 689

Answers (5)

plasmasnake
plasmasnake

Reputation: 11

var numbers =  Regex.Split(value, @".*?(.\d+).*?");

or to return each digit:

var numbers =  Regex.Split(value, @".*?(\d).*?");

Upvotes: 0

Meh
Meh

Reputation: 607

I will re-use my code from another question:

    private void button1_Click(object sender, EventArgs e)
    {
        string sauce = htm.Text; //htm = textbox
        Regex myRegex = new Regex(@"[0-9]+(?:\.[0-9]*)?", RegexOptions.Compiled);
        foreach (Match iMatch in myRegex.Matches(sauce))
        {
            txt.AppendText(Environment.NewLine + iMatch.Value);//txt= textbox
        }

    }

If you want to play around with regex here is a good site: http://gskinner.com/RegExr/ They also have a desktop app: http://gskinner.com/RegExr/desktop/ - It uses adobe air so install that first.

Upvotes: 0

PraveenVenu
PraveenVenu

Reputation: 8337

.Net has built in feature without using RegEx.Try System.Web.HttpUtility.ParseQueryString, passing the string. You would need to reference the System.Web assembly, but it shouldn't require a web context.

  var value = "session=11;reserID=1000001";
  NameValueCollection numbers = 
      System.Web.HttpUtility.ParseQueryString(value.Replace(";","&"));

Upvotes: 0

spender
spender

Reputation: 120420

Regex
 .Matches("session=11;reserID=1000001", @"\d+") //match all digit groupings
 .Cast<Match>() //promote IEnumerable to IEnumerable<Match> so we can use Linq
 .Select(m => m.Value) //for each Match, select its (string) Value
 .ToArray() //convert to array, as per question

Upvotes: 1

Joey
Joey

Reputation: 354456

You probably were on the right track but forgot the character class:

Regex.Split(value, @"[^\d]+");

You can also write it shorter by using \D+ which is equivalent.

However, you'd get an empty element at the start of the returned array, so caution when consuming the result. Sadly, Regex.Split() doesn't have an option that removes empty elements (String.Split does, however). A not very pretty way of resolving that:

Regex.Replace(value, @"[^\d;]", "").Split(';');

based on the assumption that the semicolon is actually the relevant piece where you want to split.

Quick PowerShell test:

PS> 'session=11;reserID=1000001' -replace '[^\d;]+' -split ';'
11
1000001

Another option would be to just skip the element:

Regex.Split(...).Skip(1).ToArray();

Upvotes: 2

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