Reputation: 39427
I have a method (static in this case) and I can't quite figure out the exact syntax for defining it.
static member FindPath : Queue<Node> startNode : Node endNode : Node nodes : List<Node> =
//this method will call two other to be constructed methods and return a
//queue that is the return value of one of them
return new Queue<Node>()
It fails on the colon between startNode
and the first Node with:
"Syntax error in labelled type"
What would be the best way to make a method like this?
Upvotes: 1
Views: 439
Reputation: 3457
To make it multiline you can just make the calls on separate lines
static member FindPath (startNode : Node) (endNode : Node) (nodes : List<Node>) =
let resultOfMethod1 = CallMethod1()
CallMethod2()
new Queue<Node>()
Also i removed the return type because you shouldn't need it if you return a queue like that
Upvotes: 5
Reputation: 29100
static member FindPath (startNode : Node)
(endNode : Node)
(nodes : List<Node>)
: Queue<Node>
= new Queue<Node>()
Upvotes: 3