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pythonmultiplication
Corollary
Corollary

Reputation: 13

Python: division and multiplication of timedelta64 type with floats

I am having difficulties multiplying the numpy datatype timedelta64 with floats.

For a task i need to calculate the period of a star using Kepler's second law. There are a lot of data points, so I want python to calculate the area between 2 positions and divide it by the period, using following code:

D = data['data']  
vect = D-c  #Data point minus center of ellipse
date = data['time'] #time for data point in np.timedelta64
Area_tot = np.pi*np.sqrt(chi[0])*np.sqrt(chi[1])  #total area of ellipse
P = np.array([])  
for i in range(1,len(D[0])):  
    Area = LA.norm(np.cross(vect[i],vect[i-1]))/2 #usie cross product to calculate area
    Time = date[i]-date[i-1]  
    P = np.append(P,(Area_tot/Area)*Time)

When doing this, however, I get the following error: 

TypeError: ufunc 'multiply' not supported for the input types, and the inputs could 
not be safely coerced to any supported types according to the casting rule 'safe'

So, I am wondering how I can multiply the timedelta64 datatype with a float...

Thanks in advance and be gentle, I am quite new to both stackoverflow and programming :)

Upvotes: 0

Views: 1116

Answers (1)

Matthew Plourde
Matthew Plourde

Reputation: 44614

Time.tolist().total_seconds()

gets the difference as a float.

Upvotes: 1

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