CODEWITHSUNDEEP
phpmysqlarrays
user1227914
user1227914

Reputation: 3514

Checking if value exists in php array - not working?

I have the following php code that gets a serialized array from a mysql database, then unserializes it. This is working fine. The following code:

$row=mysql_fetch_array($result);
$mydata=$row[0];
$unser=unserialize($mydata);

echo "$mydata<br>";
print_r($unser);
echo "<br>";
echo $unser[1901];

The output is this:

a:2:{i:2070;s:4:"0.00";i:1901;s:4:"1.00";}
Array ( [2070] => 0.00 [1901] => 1.00 ) 
1.00

So far, so good. Now, I'm trying to write the code so that it checks if the array key 1901 exists. For that, I tried this:

$search_array = $unser;
if (array_key_exists('1901', $search_array)) {
     echo "The key 1901 is in the array";
}

However that is returning an error. What am I doing wrong?

Upvotes: 6

Views: 1195

Answers (2)

Gabriel Santos
Gabriel Santos

Reputation: 4974

With the following code:

$mydata= 'a:2:{i:2070;s:4:"0.00";i:1901;s:4:"1.00";}';
$unser=unserialize($mydata);

echo "$mydata<br>";
print_r($unser);
echo "<br>";
echo $unser['1901'];

$search_array = $unser;
if (array_key_exists('1901', $search_array)) {
     echo "<br />The key 1901 is in the array";
}

It will work correctly:

a:2:{i:2070;s:4:"0.00";i:1901;s:4:"1.00";}
Array ( [2070] => 0.00 [1901] => 1.00 )
1.00
The key 1901 is in the array

Check if you have more code after the lines of code you have posted. I think is another piece of code which is confusing you.

Upvotes: 4

David
David

Reputation: 4361

echo $unser[1901];

should be

echo $unser['1901'];

Also you can do

if(isset($unser['1901'])) { }

instead of array_key_esists()

Upvotes: -1

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