CODEWITHSUNDEEP
java
ASD
ASD

Reputation: 735

What operations are atomic operations

I am little confused...

Is it true that reading\writing from several threads all except long and double are atomic operations and it's need to use volatile only with long and double?

Upvotes: 6

Views: 374

Answers (4)

John Vint
John Vint

Reputation: 40276

Let's not confuse atomic with thread-safe. Long and double writes are not atomic underneath because each is two separate 32 bit stores. Storing and loading non long/double fields are perfectly atomic assuming they are not a compound writes (i++ for example).

By atomic I mean you will not read some garbled object as a result of many threads writing different objects to the same field.

From Java Concurrency In Practice 3.1.2

Out-of-thin-aire safety: When a thread reads a variable without synchronization, it may see a stale value, but at least it sees a value that was actually placed there by some thread rather than some random value. This is true for all variables, except 64-bit long and double, which are not volatile. The JVM is permitted to treat 64-bit read or write as two seperate 32-bit operations which are not atomic.

Upvotes: 3

Louis Wasserman
Louis Wasserman

Reputation: 198561

It sounds like you're referring to this section of the JLS. It is guaranteed for all primitive types -- except double and long -- that all threads will see some value that was actually written to that variable. (With double and long, the first four bytes might have been written by one thread, and the last four bytes by another thread, as specified in that section of the JLS.) But they won't necessarily see the same value at the same time unless the variable is marked volatile.

Even using volatile, x += 3 is not atomic, because it's x = x + 3, which does a read and a write, and there might be writes to x between the read and the write. That's why we have things like AtomicInteger and the other utilities in java.util.concurrent.

Upvotes: 8

ratchet freak
ratchet freak

Reputation: 48226

volatile has other semantics than just writing the value atomically

it means that other threads can see the updated value immediately (and that it can't be optimized out)

Upvotes: 0

Makoto
Makoto

Reputation: 106518

That doesn't sound right.

An atomic operation is one that forces all threads to wait to access a resource until another thread is done with it. I don't see why other data types would be atomic, and others not.

Upvotes: 0

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