Reputation: 1849
I'm using OpenCV for object detection and one of the operations I would like to be able to perform is a per-pixel square root. I imagine the loop would be something like:
IplImage* img_;
...
for (int y = 0; y < img_->height; y++) {
for(int x = 0; x < img_->width; x++) {
// Take pixel square root here
}
}
My question is how can I access the pixel value at coordinates (x, y) in an IplImage object?
Upvotes: 2
Views: 7300
Reputation:
please use the CV_IMAGE_ELEM macro. Also, consider using cvPow with power=0.5 instead of working on pixels yourself, which should be avoided anyways
Upvotes: 1
Reputation: 5596
You may find several ways of reaching image elements in Gady Agam's nice OpenCV tutorial here.
Upvotes: 0
Reputation: 1082
OpenCV IplImage is a one dimensional array. You must create a single index to get at image data. The position of your pixel will be based on the color depth, and number of channels in your image.
// width step
int ws = img_->withStep;
// the number of channels (colors)
int nc = img_->nChannels;
// the depth in bytes of the color
int d = img_->depth&0x0000ffff) >> 3;
// assuming the depth is the size of a short
unsigned short * pixel_value = (img_->imageData)+((y*ws)+(x*nc*d));
// this gives you a pointer to the first color in a pixel
//if your are rolling grayscale just dereference the pointer.
You can pick a channel (color) by moving over pixel pointer pixel_value++. I would suggest using a look up table for square roots of pixels if this is going to be any sort of real time application.
Upvotes: 1
Reputation: 5021
Assuming img_ is of type IplImage, and assuming 16 bit unsigned integer data, I would say
unsigned short pixel_value = ((unsigned short *)&(img_->imageData[img_->widthStep * y]))[x];
See also here for IplImage definition.
Upvotes: 3