CODEWITHSUNDEEP
cmakefile
eduardomoroni
eduardomoroni

Reputation: 4600

How to make `make` make an a executable for each C file in a folder?

My question is deceptively simple, but I have lost several hours of study trying to get the solution. I'm trying to create a Makefile that builds an executable for each .c file in a directory.

I have tried the following:

CC = gcc
SRCS = $(wildcard *.c)
OBJS = $(patsubst %.c,%.o,$(SRCS))

all: $(OBJS)
$(CC) $< -o $@

%.o: %.c
    $(CC) $(CPFLAGS)  -c  $<

but this way it is creating only .o files, and not any executables. I need a rule that makes an executable for each of these .o files. Something like the following:

gcc src.o -o src

Upvotes: 8

Views: 3572

Answers (4)

Joaquin
Joaquin

Reputation: 11

This is the Makefile I use to compile a bunch of scheme files.

SRCS = $(wildcard *.scm)

all: $(SRCS:.scm=)

%: %.scm
    chicken-csc -o $@ $<

Upvotes: 1

Idelic
Idelic

Reputation: 15582

Try the following:

% : %.c
    $(CC) $(CFLAGS) $(CPPFLAGS) -o $@ $<
all: $(basename $(wildcard *.c))

and you don't even need the first two lines, as make knows how to compile and link .c files into executables. Still, it is often necessary to change make's built-in recipes.

Upvotes: 1

Joseph Quinsey
Joseph Quinsey

Reputation: 9972

rob's answer doesn't seem to work on my machine. Perhaps, as the complete Makefile:

SRCS = $(wildcard *.c)

all: $(SRCS:.c=)

.c:
     gcc $(CPFLAGS) $< -o $@

(The last two lines, are on my machine, unnecessary, as the default rules are adequate.)

Upvotes: 7

rob
rob

Reputation: 2133

Your all is telling it just to build the object files. Add something like

EXEC = $(patsubst %.c,%,$(SRCS))

all: $(EXEC)

Upvotes: 2

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