CODEWITHSUNDEEP
jqueryajax
user455318
user455318

Reputation: 3346

validation with json - ajax

If i have this json response 

{"error":"repeated"}

Why the alert is not showed? It is needed put somewhere dataType: "json" ?

$(function () {
        $("#box a").click(function () {
            var selectedId = $(this).attr("class");

            $.post("new_list.php", {
                id_user: <?php echo $id;?>,
                id_list: selectedId
            }, function (data) {
                   if(data.error == 'repeated') {
                        alert("error");
                   }
            }); 
        }); 
    });

thanks

Upvotes: 1

Views: 156

Answers (4)

Kevin Bowersox
Kevin Bowersox

Reputation: 94499

$(function () {
        $("#box a").click(function () {
            var selectedId = $(this).attr("class");

            $.post("new_list.php", {
                id_user: <?php echo $id;?>,
                id_list: selectedId
            }, function (data) {
                   if(data.error == 'repeated') {
                        alert("error");
                   }
            },dataType: "json" ); 
        }); 
    });

The following snippet will let jquery know your expecting json.

Upvotes: 0

bart s
bart s

Reputation: 5100

Check if your reply is a string instead of an object. Then you must call 

var obj = jQuery.parseJSON(data);

And use obj.error to check if it is 'repeated'

Upvotes: 0

Hubro
Hubro

Reputation: 59403

It would be a matter of converting the response string into a Javascript object:

function (data) {
    // Parse the JSON
    data = JSON.parse(data);

    if(data.error == 'repeated') {
        alert("error");
    }
}

Although you could just use the jQuery.getJSON function instead, saving yourself some trouble

Upvotes: 1

Alex Turpin
Alex Turpin

Reputation: 47776

It's not going to automatically parse it as JSON unless you tell it to.

$(function () {
    $("#box a").click(function () {
        var selectedId = $(this).attr("class");

        $.post("new_list.php", {
            id_user: <?php echo $id;?>,
            id_list: selectedId
        }, function (data) {
               if(data.error == 'repeated') {
                    alert("error");
               }
        },
        "json"); //Here, add this as last parameter
    }); 
});

Upvotes: 2

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