CODEWITHSUNDEEP
pythonlistinttypeerror
kommihe
kommihe

Reputation: 571

TypeError: 'int' object is unsubscriptable - python

I'm trying to make a small program that gets a random website and counts the elements.

Here is my error:

Traceback (most recent call last):
  File "elements counter.py", line 23, in <module>
    if elem[1] == string:
TypeError: 'int' object is unsubscriptable

Here is my code:

from urllib2 import Request, urlopen, URLError

print 'Fetching URL..'

try:
    html = urlopen(Request("http://www.randomwebsite.com/cgi-bin/random.pl"))
except URLError:
    html = urlopen(Request("http://www.randomwebsitemachine.com/random_website/"))

print 'Loading HTML..'

ellist = [(None,None),]
isel = False
string = ''

for char in html.read():
    if char == '<':
        isel=True
    elif isel:
        if char == ' ' or char == '>':
            if string in ellist:
                for elem in ellist:
                    if elem[1] == string:
                        elem[0] += 1
            else:
                ellist += (1,string)
            isel = False
            string = ''
        else:
            string += char

print sorted(ellist, key = lambda tempvar: tempvar[0])

html.close()
raw_input()

Please point out if you find anything more wrong in the code.

Upvotes: 0

Views: 2612

Answers (1)

agf
agf

Reputation: 176910

When you do

            ellist += (1,string)

it's the same as 

            ellist.extend((1,string))

so ellist looks something like

[(None, None), 1, string]

so when you get to the second element in the for loop, it's an int not a tuple.

Instead, do

            ellist.append((1,string))

or, if you really want to use +=,

            ellist += [(1,string)]

The rest of your code looks basically right, but note you won't properly handle angle brackets in quotes or in HTML comments. If you want to parse HTML, use one of the many HTML parsers out there, like Python's HTMLParser module, lxml, or BeautifulSoup.

Upvotes: 2

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