CODEWITHSUNDEEP
phpstringcastingtype-conversioninteger
kman99
kman99

Reputation: 7665

Converting an integer to a string in PHP

Is there a way to convert an integer to a string in PHP?

Upvotes: 649

Views: 1716107

Answers (15)

gewel
gewel

Reputation: 451

Use:

$intValue = 1;
$string = sprintf('%d', $intValue);

Or it could be:

$string = (string)$intValue;

Or:

settype($intValue, 'string');

Upvotes: 16

Microprocessor Cat
Microprocessor Cat

Reputation: 117

Warning: the below answer is based on the wrong premise. Casting 0 number to string always returns string "0", making the code provided redundant.

All these answers are great, but they all return you an empty string if the value is zero.

Try the following:

    $v = 0;

    $s = (string)$v ? (string)$v : "0";

Upvotes: 10

temur Usmonaliyev
temur Usmonaliyev

Reputation: 9

My situation :

echo strval("12"); => 12
echo strval("0"); => "0"

I'm working ...

$a = "12";
$b = "0";
echo $a * 1; => 12
echo $b * 1; => 0

Upvotes: 0

Joseph Tam
Joseph Tam

Reputation: 1

I tried all the methods above yet I got "array to string conversion" error when I embedded the value in another string. If you have the same problem with me try the implode() function. example:

$integer = 0;    
$id = implode($integer);    
$text = "Your user ID is: ".$id ;

Upvotes: -1

Chris Thompson
Chris Thompson

Reputation: 16871

You can use the strval() function to convert a number to a string.

From a maintenance perspective its obvious what you are trying to do rather than some of the other more esoteric answers. Of course, it depends on your context.

$var = 5;

// Inline variable parsing
echo "I'd like {$var} waffles"; // = I'd like 5 waffles

// String concatenation 
echo "I'd like ".$var." waffles"; // I'd like 5 waffles

// The two examples above have the same end value...
// ... And so do the two below

// Explicit cast 
$items = (string)$var; // $items === "5";

// Function call
$items = strval($var); // $items === "5";

Upvotes: 1008

Kaushik shrimali
Kaushik shrimali

Reputation: 1228

$amount = 2351.25;
$str_amount = "2351.25";

$strCorrectAmount = "$amount";
echo gettype($strCorrectAmount);    //string

So the echo will be return string.

Upvotes: 0

Alana Storm
Alana Storm

Reputation: 166156

There are a number of ways to "convert" an integer to a string in PHP.

The traditional computer science way would be to cast the variable as a string:

$int = 5;
$int_as_string = (string) $int;
echo $int . ' is a '. gettype($int) . "\n";
echo $int_as_string . ' is a ' . gettype($int_as_string) . "\n";

You could also take advantage of PHP's implicit type conversion and string interpolation:

$int = 5;
echo $int . ' is a '. gettype($int) . "\n";

$int_as_string = "$int";
echo $int_as_string . ' is a ' . gettype($int_as_string) . "\n";

$string_int = $int.'';
echo $int_as_string . ' is a ' . gettype($int_as_string) . "\n";

Finally, similar to the above, any function that accepts and returns a string could be used to convert and integer. Consider the following:

$int = 5;
echo $int . ' is a '. gettype($int) . "\n";

$int_as_string = trim($int);
echo $int_as_string . ' is a ' . gettype($int_as_string) . "\n";

I wouldn't recommend the final option, but I've seen code in the wild that relied on this behavior, so thought I'd pass it along.

Upvotes: 13

merkuro
merkuro

Reputation: 6177

I would say it depends on the context. strval() or the casting operator (string) could be used. However, in most cases PHP will decide what's good for you if, for example, you use it with echo or printf...

One small note: die() needs a string and won't show any int :)

Upvotes: 0

Andrew Dunkman
Andrew Dunkman

Reputation: 1131

You can either use the period operator and concatenate a string to it (and it will be type casted to a string):

$integer = 93;
$stringedInt = $integer . "";

Or, more correctly, you can just type cast the integer to a string:

$integer = 93;
$stringedInt = (string) $integer;

Upvotes: 4

Sev
Sev

Reputation: 15737

$foo = 5;

$foo = $foo . "";

Now $foo is a string.

But, you may want to get used to casting. As casting is the proper way to accomplish something of that sort:

$foo = 5;
$foo = (string)$foo;

Another way is to encapsulate in quotes:

$foo = 5;
$foo = "$foo"

Upvotes: 57

UserBSS1
UserBSS1

Reputation: 2231

There are many possible conversion ways:

$input => 123
sprintf('%d',$input) => 123
(string)$input => 123
strval($input) => 123
settype($input, "string") => 123

Upvotes: 5

Iyti
Iyti

Reputation: 19

You can simply use the following:

$intVal = 5;
$strVal = trim($intVal);

Upvotes: -3

Arthur Kushman
Arthur Kushman

Reputation: 84

$integer = 93;
$stringedInt = $integer.'';

is faster than 

$integer = 93;
$stringedInt = $integer."";

Upvotes: -5

troelskn
troelskn

Reputation: 117615

As the answers here demonstrates nicely, yes, there are several ways. However, in PHP you rarely actually need to do that. The "dogmatic way" to write PHP is to rely on the language's loose typing system, which will transparently coerce the type as needed. For integer values, this is usually without trouble. You should be very careful with floating point values, though.

Upvotes: 2

Sanjay Sheth
Sanjay Sheth

Reputation: 1619

There's many ways to do this.

Two examples:

 $str = (string) $int;
 $str = "$int";

See the PHP Manual on Types Juggling for more.

Upvotes: 120

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