CODEWITHSUNDEEP
phpstringcastingint
Manuel Ramos
Manuel Ramos

Reputation: 41

Cast string to integer in PHP

I've been trying to convert string to int in PHP to operate on it, but PHP keeps interpreting it as 0.

var_dump ($Pux); // output: string (6) "89"

I have tried several ways like

(int) $Pux,
intval($Pux)
settype($Pux, "integer")

But they all give me 0 instead of 89.

How should this be done?

Upvotes: 2

Views: 16856

Answers (6)

Barthelemy Antoine
Barthelemy Antoine

Reputation: 1

I had the same mistake. Indeed when i did var_dump($myvar). it returns string(2) "89" and when i did all the casts fonctions it returned me 0. I search and finally the answer is in this page. So I share with you what i learned. You have just to do a regex php : $myvar = preg_replace("/[^0-9,.]","",$myvar). It removes all the not number in your string (in my case the string(2)).

Upvotes: 0

Taron Saribekyan
Taron Saribekyan

Reputation: 1390

As var_dump($Pux); outputs string(6) "89" (not string(2)), it means your string contains 6 symbol, I think they are 4 single brackets (') and 89. So try to remove brackets from your string:

$Pux = str_replace("'", '', $Pux);

or remove double brackets too (for safe)

$Pux = strtr($Pux, array("'" => '', '"' => ''));

EDITED

will be good to remove all non numeric values:

$Pux = preg_replace("/[^0-9,.]/", "", $Pux);

and then convert to integer.

Thanks.

Upvotes: 0

lipinf
lipinf

Reputation: 133

The code below removes the non numeric characters::

function numeric( $st_data )
    {
        $st_data = preg_replace("([[:punct:]]|[[:alpha:]]| )",'',$st_data);
        return $st_data;    
    }

Upvotes: 0

Kheshav Sewnundun
Kheshav Sewnundun

Reputation: 1244

You can convert string to integer in two ways:

Typecasting or intval function 

<?php
 $pux = "89";
 var_dump($pux);
 $pux = (int) $pux;
 var_dump($pux);
 $pux = "89";
 $pux =  intval($pux);
 var_dump($pux);
?>

Upvotes: 0

Peter Blue
Peter Blue

Reputation: 192

The easiest way to convert a string to a number:-

<?php
$Pux = "89"; // Or any other number
$Num = (int) $pux;
?>

If you are still getting a zero there might be some odd, invisible chars in front of the number. To test for that :-

echo "($Pux)";

Upvotes: 0

RiggsFolly
RiggsFolly

Reputation: 94682

There is not problem if you dont put spaces between $ and varname and assign the result of the cast to a variable.

<?php 
    $Pux = "89";
    var_dump ($Pux);
    $t = (int)$Pux;
    var_dump ($t);
?>

Output = 

string(2) "89"
int(89)

Upvotes: 3

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